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mr_godi [17]
3 years ago
15

Add the following numbers a)and b)answers please ​

Mathematics
2 answers:
Drupady [299]3 years ago
4 0
Answer: a) 3 2/3, b) 5 2/5

Explanation:

a) 5/3 + 6/3 = 11/3 = 3 2/3

b) 12/5 + 15/5 = 27/5 = 5 2/5
Paraphin [41]3 years ago
4 0

Answer:

11/3                  27/5      my man

Step-by-step explanation:

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Pls help ;-;
anyanavicka [17]

Answer:

C

Step-by-step explanation:

A closed circle means inclusive, and -2 is included in values that would make the equation true. Then you just have to test another number greater than and less than -2 to see which way the arrow should point.

-3(-3) + 1 < 7

9 + 1 < 7

10 < 7 FALSE

-3(0) + 1 < 7

1 < 7 TRUE

All values (including -2) will make this equation true

6 0
3 years ago
Read 2 more answers
Please help this was due today
Aleksandr [31]

Answer:

Why didn't u do it ?

Step-by-step explanation:

i know dumb question but i got points so i'm a OK if u were wondering

8 0
3 years ago
HELP I WILL MARK YOU BRAINLIEST!! IT DOESN’T GIVE ME THE OPTION UNTIL TWO PEOPLE HAVE ANSWERED
TEA [102]

Answer:

B. Same distance and same direction

Step-by-step explanation:

The points have to move together while maintaining the same shape.

3 0
3 years ago
Given that the quadratic equation has equal roots (k^2-1)x^2-2kx-3k-1=0
Alik [6]

Answer:

(See explanation for further details)

Step-by-step explanation:

The real expression is:

(k^{2}-1)\cdot x{{2} - 2\cdot k \cdot x - 3\cdot k + 1 = 0

The general equation for the second-order polynomial is:

x = \frac{2\cdot k \pm \sqrt{4\cdot k^{2}-4\cdot (k^{2}-1)\cdot (-3\cdot k + 1)}}{k^{2}-1}

This condition must be observed for the case of a quadratic equation with equal roots:

4\cdot k^{2} - 4\cdot (k^{2}-1)\cdot (-3\cdot k + 1) = 0

k^{2} + (k^{2}-1)\cdot (3\cdot k + 1) = 0

k^{2} + 3\cdot k^{3} - 3\cdot k - k^{2}-1 = 0

3\cdot k^{3} - 3\cdot k - 1 = 0

7 0
3 years ago
Does anyone like math in this world?
larisa86 [58]

Answer:

i mean math is my second favorite subject

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
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