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mr_godi [17]
3 years ago
15

Add the following numbers a)and b)answers please ​

Mathematics
2 answers:
Drupady [299]3 years ago
4 0
Answer: a) 3 2/3, b) 5 2/5

Explanation:

a) 5/3 + 6/3 = 11/3 = 3 2/3

b) 12/5 + 15/5 = 27/5 = 5 2/5
Paraphin [41]3 years ago
4 0

Answer:

11/3                  27/5      my man

Step-by-step explanation:

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3 to the -2nd power??
WARRIOR [948]

Answer:3^2=9

U are gonna times 3 two times

Example:3x3=9

7 0
3 years ago
<img src="https://tex.z-dn.net/?f=x%5E%7B2%7D%20%20%2B%2036x%20%2B%20324%20%3D%20%28x%20%2B%20m%29%5E%7B2%7D%20" id="TexFormula1
nasty-shy [4]

Answer:

B. 18

Step-by-step explanation:

x^{2} + 36x + 324 = (x + m)^{2}

(x+18)^{2}= (x + m)^{2}

\cancel x+18= \cancel x + m

18= m

5 0
2 years ago
Read 2 more answers
PLEASE HELP ASAAAAPPPPPP
monitta
The correct answer is A

4 0
3 years ago
Read 2 more answers
4. I need help with question in the attached picture!
Arisa [49]

ANSWER

D. 13

EXPLANATION

We have

f(x) =  \frac{2x + 1}{x - 4}

To find

{f}^{ - 1} (3)

means we want to find an x-value whose image is 3.

\frac{2x + 1}{x - 4}  = 3

We cross multiply,

2x + 1 = 3(x - 4)

Expand:

2x + 1 = 3x - 12

Combine like terms,

3x - 2x = 12 + 1

x = 13

\therefore{f}^{ - 1} (3)= 13

4 0
3 years ago
Read 2 more answers
I need the whole solution
ddd [48]

Confused what the question is. Are you looking for the product or the zeroes?

If you are looking for the product, then:

Use foil to get: sec²(1) - sec²(-csc²) -1(1) -1(-csc²)

= sec² + sec²csc² - 1 + csc²

= sec²csc² + sec² + csc² - 1

= sec²csc² + 1 - 1 (NOTE: sec² + csc² = 1 is an identity)

= sec²csc²

Answer: sec²csc²

***************************************************

If you are looking for the zeroes, then:

Using the zero product property, set each factor equal to zero and solve.

<u>First factor:</u>

sec²Θ - 1 = 0

sec²Θ = 1

secΘ = 1, -1

remember that secΘ is \frac{1}{cos}

\frac{1}{cos} = 1 \frac{1}{cos} = -1

cross multiply to get:

cosΘ = 1 cosΘ = -1

use the unit circle (or a calculator) to find that Θ = 0 and π

<u>Second factor:</u>

1 - csc²Θ = 0

1 = csc²Θ

1, -1 = cscΘ

remember that cscΘ is \frac{1}{sin}

\frac{1}{sin} = 1 \frac{1}{sin} = -1

cross multiply to get:

sinΘ = 1 sinΘ = -1

use the unit circle (or a calculator) to find that Θ = \frac{\pi}{2} and \frac{3\pi}{2}

Answer: 0, π, \frac{\pi}{2} , \frac{3\pi}{2}

7 0
3 years ago
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