The expression coud be re written:
12x²y/2xy + 6xy/2xy + 4x²/2xy . Simplify numerator & denominator whenever it is possible:
6x-3+2x/y
Answer:
-25
Step-by-step explanation:
(1) y = -2x²
(2) y = 2x² + k Subtract (1) from (2)
0 = 4x² + k Subtract 4x² from each side
k = -4x²
The parabolas are <em>symmetrical about the y-axis.</em>
Segment AB = 5, so x = +2.5 and x = +2.5.
k = -4(±2.5)² = -4 × 6.25 = -25
For this case we have the following functions:

When composing the functions we have:

Substituting values we have:

Rewriting:

The function has a horizontal asymptote at y = 3.
Therefore, the range of the function is all reals minus y = 3.
Answer:
option 3
Answer:
See solution below
Step-by-step explanation:
Let the coordinate's of A and B be (1, 0) and (2,4) respectively
midpoint M (X, Y) = [(x1+x2/2, y1+y2/2)]
X = x1+x2/2
X = 1+2/2
X = 3/2
X = 1.5
Y = y1+y2/2
Y = 0+4/2
Y = 4/2
Y = 2
Hence the required midpoint (X, Y) is (1.5, 2)
Slope m = y2-y1/x2-x1
m = 4-0/2-1
m = 4/1
m = 4
Hence the slope is 4
<em>Note that the coordinates are assumed but the same calculation can be employed for any other coordinates</em>
Answer:
0.5* sin(x)
Step-by-step explanation:
As well known sin (2A)= 2sin(A)*cos(A)
As in our case A=x/2 => cos(x/2*sin(x/2)=1/2*sin(x)=0.5*sin(x)