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Kaylis [27]
3 years ago
11

An electric bell is kept under a bell jar in which a vacuum has been created. Slowly air is introduced in to the jar. What will

happen to the sound of the electric bell?Select one of the options below as your answer:. A. It will increase until it reaches its maximum.. B. It will decrease until it stops.. C. It will not change.. D. It will increase and decrease periodically. .E. It will decrease exponentially
Physics
2 answers:
Aleks [24]3 years ago
8 0
A. Increase until it reaches it's maximum. Sound travels through air and as the amount of air in the jar increases, the loudness or amplitude of the bell increases until it reaches it's maximum at normal air pressure.
ser-zykov [4K]3 years ago
4 0

The sound of the electric bell will increase until it reaches its maximum. The correct answer between all the choices given is the first choice or letter A. I am hoping that this answer has satisfied your query about and it will be able to help you, and if you’d like, feel free to ask another question.

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When the voltage is
gizmo_the_mogwai [7]

Explanation:

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7 0
3 years ago
How did the angular acceleration change with the new moment of inertia? was your prediction correct?
elena55 [62]

In Newtonian physics, the acceleration of a body is inversely proportional to mass. In Newtonian rotational physics, angular acceleration is inversely proportional to the moment of inertia of a frame.

The moment of Inertia is frequently given the image I. it's miles the rotational analog of mass. The moment of inertia of an object is a measure of its resistance to angular acceleration. because of its rotational inertia, you want torque to change the angular pace of an object. If there may be no net torque acting on an object, its angular speed will no longer change.

In linear momentum, the momentum p is the same as the mass m instances of the velocity v; whereas for angular momentum, the angular momentum L is the same as the instant of inertia I times the angular pace ω.

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6 0
1 year ago
Raindrops are falling straight down at 11 m/s when suddenly the wind starts blowing horizontally at a brisk 5.0 m/s. From your p
Bumek [7]

Answer: 24.4 degrees to the vertical

Explanation:

Vertical component of raindrop speed = 11m/s

Horizontal component of wind = 5m/s

In this case, all we have to do is to use trigonometric ratios of angles to sides as in a triangle

Doing this, we see that

tan (theta) = 5/11

(Where theta is the angle made with the vertical by the rain after impact)

Tan being opposite/adjacent

Arc sin (5/11) gives us 24.44 degrees to the vertical

8 0
3 years ago
In the formula for magnetic deflection, FM is equal to qvB. Match each symbol in this formula with what it represents.
slava [35]

Answer:

1.F_m-Deflection force

2.q-Charge

3.v-Velocity of the charge

4.B-Perpendicular magnetic field strength

Explanation:

We are given that magnetic  deflection

F_m=qvB

We have to match each symbol in formula with what it  represents.

In this formula

F_m=Deflection force

q=Charge of particle

v=Velocity of charge

B=Perpendicular magnetic field strength

Therefore,

1.F_m-Deflection force

2.q-Charge

3.v-Velocity of the charge

4.B-Perpendicular magnetic field strength

8 0
3 years ago
Read 2 more answers
You're driving down the highway late one night at 20 m/s when a deer steps onto the road 35 m in front of you. You reaction time
bearhunter [10]

Answer:

Explanation:

Discount the time here; it's not important. It doesn't tell you how long it takes the car to stop, it only refers to reaction time, which means nothing in the scheme of things.

The useful info is as follows:

initial velocity = 20 m/s

final velocity = 0 m/s

a = -10 m/s/s

and we are looking for the displacement. Use the following equation:

v^2=v_0^2+2aΔx

where v is the final velocity, v₀ is the initial velocity, a is the deceleration (since it's negative), and Δx is displacement. Filling in:

0^2=(20)^2+2(-10)Δx and

0 = 400 - 20Δx and

-400 = -20Δx so

Δ = 20 meters

3 0
3 years ago
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