Answer:
Explanation:
We know that
Δr = r₁ - r₀
r₀ = 0 i + 0 j
r₁ = (162+137*Cos(31º)+137*Cos(-48º)) i + (0+137*Sin(31º)+137*Sin(-48º)) j = (371.1028 i - 31.2506 j) ft
Δr = r₁ - r₀ = (371.1028 i - 31.2506 j) - (0 i + 0 j) = (371.1028 i - 31.2506 j) ft
Magnitude:
Δr = √((371.1028)²+(-31.2506)²) = 372.4163 ft
Angle:
tan θ = (- 31.2506 / 371.1028) = -0.0839 ⇒ θ = tan⁻¹(-0.0839) = - 4.8135º
(below the horizontal).
The formula for mass you can find from the density equation. Multiply the volume by both sides of the equation.
density = mass/volume
volume*density = mass
And there you are :)
Answer:
t = 4.58 s
Explanation:
In this problem, we need to find the time elapse between seeing lightning and hearing the thunder if the lightning strikes 1mi (5280 ft) away and the air temperature is 90.0°F.
T = 90.0°F = 32.2 °C
The speed of sound at temperature T is given by :
v = (331.3 +0.6T)
Put T = 32.2°C
So,
v = (331.3 +0.6(32.2))
= 350.62 m/s
We have, distance, d = 1 mile = 1609.34
So,

So, the required time is equal to 4.58 seconds.