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Lesechka [4]
3 years ago
15

When sound waves strike the eardrum, this membrane vibrates with the same frequency as the sound. The highest pitch that typical

humans can hear has a period of 50.0 μs. What are the frequency and angular frequency of the vibrating eardrum for this sound?
Physics
2 answers:
kherson [118]3 years ago
7 0

Answer:

Explanation:

Time period, T = 50 μs = 50 x 10^-6 s

Frequency is defined as the number of oscillations or vibrations completed in one second.

The reciprocal of time period is called frequency.

f = 1 / T

f = 1 / (50 x 10^-6)

f = 20,000 Hz

Angular frequency, ω = 2 x π x f

ω = 2 x 3.14 x 20,000

ω = 125600 rad/s

zheka24 [161]3 years ago
6 0

Answer:

<u>Frequency: </u>

The cycles or periods cover by an entity is called the frequency,f.

<u>Mathematical equation:</u> f=1/T.

<u>Unit:</u> Hertz,Hz.

<u>Angular frequency:</u>

Basically, to determine the movement of an object which is moving on a circular path, the angular velocity is the cycles or the distance covered between any points on the circular path is called as the angular frequency,ω.

<u>Formula: </u>ω = 2 x π x f.

<u>Units:</u> rad(or degree)/sec.

Explanation:

<u>We have the following data provided to us, as following:</u>

  • Time period, T = 50 μs,
  • T=50 x 10^-6 s,

  • <u>As, we have f = 1 / T</u>

  • f = 1 / (50 x 10^-6)

  • f = 20,000 Hz,
  • <u>f=20 kHz.</u>

  • <u>As, we have the following equation to put all the values then;</u>
  • <u>ω = 2 x π x f,</u>
  • ω = 2 x 3.14 x 20,000
  • <u>ω = 125600 rad/s.</u>⇒ Answer

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