Question

A scientist placed 22.854 g of sodium chloride in a beaker. He then added five times as much calcium chloride as sodium chloride. Finally, he divided the mixture evenly into four dishes. How much of the mixture did each dish contain? 28.5675 g 34.2810 g 137.1240 g 548.4960 g

Answer 1

Starts with 22.854...he then adds 5 times as much...
22.854 + 5(22.954) = 137.124
he divided mixture into 4 dishes
137.124/4 = 34.2810 grams <==

Answer 2

Answer: 34.2810 g

Step-by-step explanation:

Mass of sodium chloride in a beaker = 22.854 g

Mass of calcium chloride in a beaker = $5\times {\text {Mass of sodium chloride}}=5\times 22.854 g = 114.27 g$

Now total mass in the beaker = Mass of sodium chloride in a beaker + Mass of calcium chloride in a beaker =  22.854 g + 114.27 g = 137.124 g

Now the mixture is evenly divided into four dishes.

Amount of the mixture each dish contain = $\frac{\text {total mass in the beaker}}{4}=\frac{137.124g}{4}=34.2810g$

Thus amount of the mixture in dish is 34.2810 g.