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12345 [234]
3 years ago
15

What is the definition of carbohydrates

Chemistry
2 answers:
Mkey [24]3 years ago
7 0

Answer:

carbohydrates are energy giving foods that warm the body and could be in different forms

Firdavs [7]3 years ago
4 0

Answer and Explanation:

Carbohydrates are a type of biomolecule that the body uses primarily for energy and/or structure. They usually consist of the elements carbon (C), hydrogen (H), and oxygen (O) in a 1 : 2 : 1 ratio. For example, glucose, a carbohydrate, is C_6H_{12}O_6.

Monomers of carbohydrates are called monosaccharides, and polymers are called disaccharides if two monosaccharides are combined and polysaccharides if more than two monosaccharides are put together.

Examples of carbohydrates are sugars, starches, cellulose, lactose, sucrose, etc.

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Name the four elements on the Periodic Table that are considered METALLOIDS?​
Nimfa-mama [501]

Answer:

boron (B), silicon (Si), germanium (Ge), arsenic (As), antimony (Sb), tellurium (Te), polonium (Po) and astatine (At)

Explanation:

metalloids are elements that are in between the metals and nonmetals. they are in between because they have properties of both metals and nonmetals.

you can search "metalloids on the periodic table" and go to images to see what i mean :)

5 0
3 years ago
How many protons, and neutrons are in nuclide tin-115?
HACTEHA [7]
50 protons
65 neutrons
8 0
3 years ago
Read 2 more answers
What is the mass of 7 x 10^28 atoms of Fe?
Nostrana [21]

Answer:

6 x 10⁶ g Fe

Explanation:

Step 1: Set up dimensional analysis

7 x 10²⁸ atoms Fe (1 mol Fe/6.02 x 10²³ atoms Fe)(55.85 g Fe/1 mol Fe)

Step 2: Multiply, divide, and cancel out units

atoms Fe and atoms Fe cancel out.

mol Fe and mol Fe cancel out.

We should be left with g Fe.

7 x 10²⁸/6.02 x 10²³ = 116279 mol Fe

116279(55.85) = 6.49 x 10⁶ g Fe

Step 3: Sig figs

There is only 1 sig fig in this problem.

6.49 x 10⁶ g Fe ≈ 6 x 10⁶ g Fe

4 0
3 years ago
N
bazaltina [42]

Answer:

electron - proton

Explanation:

fsger

5 0
3 years ago
Read 2 more answers
Suppose of copper(II) acetate is dissolved in of a aqueous solution of sodium chromate. Calculate the final molarity of acetate
uranmaximum [27]

Answer:

0.0714 M for the given variables

Explanation:

The question is missing some data, but one of the original questions regarding this problem provides the following data:

Mass of copper(II) acetate: m_{(AcO)_2Cu} = 0.972 g

Volume of the sodium chromate solution: V_{Na_2CrO_4} = 150.0 mL

Molarity of the sodium chromate solution: c_{Na_2CrO_4} = 0.0400 M

Now, when copper(II) acetate reacts with sodium chromate, an insoluble copper(II) chromate is formed:

(CH_3COO)_2Cu (aq) + Na_2CrO_4 (aq)\rightarrow 2 CH_3COONa (aq) + CuCrO_4 (s)

Find moles of each reactant. or copper(II) acetate, divide its mass by the molar mass:

n_{(AcO)_2Cu} = \frac{0.972 g}{181.63 g/mol} = 0.0053515 mol

Moles of the sodium chromate solution would be found by multiplying its volume by molarity:

n_{Na_2CrO_4} = 0.0400 M\cdot 0.1500 L = 0.00600 mol

Find the limiting reactant. Notice that stoichiometry of this reaction is 1 : 1, so we can compare moles directly. Moles of copper(II) acetate are lower than moles of sodium chromate, so copper(II) acetate is our limiting reactant.

Write the net ionic equation for this reaction:

Cu^{2+} (aq) + CrO_4^{2-} (aq)\rightarrow CuCrO_4 (s)

Notice that acetate is the ion spectator. This means it doesn't react, its moles throughout reaction stay the same. We started with:

n_{(AcO)_2Cu} = 0.0053515 mol

According to stoichiometry, 1 unit of copper(II) acetate has 2 units of acetate, so moles of acetate are equal to:

n_{AcO^-} = 2\cdot 0.0053515 mol = 0.010703 mol

The total volume of this solution doesn't change, so dividing moles of acetate by this volume will yield the molarity of acetate:

c_{AcO^-} = \frac{0.010703 mol}{0.1500 L} = 0.0714 M

8 0
3 years ago
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