Both containers have the same number of molecules= 5.62 x 10²³
<h3>Further explanation</h3>
Given
22.4 L of hydrogen gas
22.4 L of oxygen gas
25°C and 1 atm.
Required
true statement
Solution
Conditions at T 25 ° C and P 1 atm are stated by RTP (Room Temperature and Pressure). Vm in this condition = 24 liters / mol
and from Avogadro's Law :
<em>At the same temperature and pressure, the ratio of gas volume will be equal to the ratio of gas moles </em>
So two gas have the same molecules
1 mol = 6.02 x 10²³ molecules
24 L = 1 mol, so for 22.4 L :
The empirical formula for the caproic acid, given the combustion analysis data is C₃H₆O
We'll begin bey obtaining the mass of carbon, hydrogen and oxygen in the compound. This is illustrated below:
How to determine the mass of C
- Mass of CO₂ = 9.78 g
- Molar mass of CO₂ = 44 g/mol
- Molar of C = 12 g/mol
- Mass of C =?
Mass of C = (12 / 44) × 9.78
Mass of C = 2.67 g
How to determine the mass of H
- Mass of H₂O = 20.99 g
- Molar mass of H₂O = 18 g/mol
- Molar of H = 2 × 1 = 2 g/mol
- Mass of H =?
Mass of H = (2 / 18) × 4
Mass of H = 0.44 g
How to determine the mass of O
- Mass of compound = 4.30 g
- Mass of C = 2.67 g
- Mass of H = 0.44 g
- Mass of O =?
Mass of O = (mass of compound) – (mass of C + mass of H)
Mass of O = 4.30 – (2.67 + 0.44)
Mass of O = 1.19 g
<h3>How to determine the empirical formula </h3>
The empirical formula of the compound can be obtained as follow:
- C = 2.67 g
- H = 0.44 g
- O = 1.19 g
- Empirical formula =?
Divide by their molar mass
C = 2.67 / 12 = 0.2225
H = 0.44 / 1 = 0.44
O = 1.19 / 16 = 0.074
Divide by the smallest
C = 0.2225 / 0.074 = 3
H = 0.44 / 0.0744 = 6
O = 0.074 / 0.074 = 1
Thus, the empirical formula of the compound is C₃H₆O
Learn more about empirical formula:
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Answer:
178.1g
Explanation:
m= n × MM
where
m is mass
n is moles &
MM is molecular mass
The molecular mass of cobalt is 58.933195. With this information and the number of moles given in the question, we can perform the calculation
m= 3.022 × 58.933195
m=178.09611529
m= 178.1g
Answer:
<h3>The answer is 82.86 cm³</h3>
Explanation:
The volume of a substance when given the density and mass can be found by using the formula
From the question
mass of wood = 44 g
density = 0.531 g/cm³
It's volume is
We have the final answer as
<h3>82.86 cm³</h3>
Hope this helps you
Answer:
K₃PO₄ + 3HCl ⇒ 3KCl + H₃PO₄
Explanation:
practice these, it gets easier. goal is to match the amount of reactants and products on both sides of the equation. cheers!
