Explanation:
Mole ratio of Oxygen to Hydrogen gas = 1 : 2.
If we use 3.0 moles of oxygen gas, we would need 3.0 * 2 = 6.0 mol of hydrogen gas.
However we only have 4.2 mol of hydrogen. Therefore hydrogen is limiting and oxygen is in excess. (B)
4 covalent ---because bromine is a non-metal and each atom must share electrons in order to satisfy the octet rule. In a covalent bond, two atoms share a pair of electrons. IOnic bonds form as a result of the transfer of electrons from one atom to another.
<h2><u>Q</u><u>u</u><u>e</u><u>s</u><u>t</u><u>i</u><u>o</u><u>n</u>:-</h2>
Density = 11g/cm³, volume = 2cm³. What is the mass ?
<h2><u>S</u><u>o</u><u>l</u><u>u</u><u>t</u><u>i</u><u>o</u><u>n</u>:-</h2>
We know,
So, Mass = 11g/cm³ × 2cm³
Mass = 22 g
<h3>The mass is <u>2</u><u>2</u><u> </u><u>g</u>. [Answer]</h3>
Answer:
[Kr] 4d10 5s2 5p4
Explanation:
The Symbol I represents Iodine. It has atomic number of 53. The full electronic configuration is given as;
1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p6 4d10 5s2 5p5
However the question requested for the configuration of I+.
I+ is a cation and it simply refers to an iodine atom that has lost a single electron. The electronic configuration of I+ is given as;
1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p6 4d10 5s2 5p4
Using Noble gas shorthand representation, we have;
[Kr] 4d10 5s2 5p4
Move the decimal point over to the left 2 spaces and mult by the number of ml .
473 ml times 0.70 = 331.1 ml
