Question

50.0 g of NaNO3 are dissolved into enough water to make 250 mL of solution. What is the molarity of this solution?

Answer 1

Answer:

2.35 M

Explanation:

Molarity is mol/L of solution. We have to convert the g to mol and the mL to L. G to mol uses the molar mass of the compound. The molar mass of NaNO₃ is 85.00g/mol.

$50.0gNaNO3*\frac{1molNaNO3}{85.00gNaNO3} = 0.588molNaNO3$

Then you have to convert mL to L.

$250mL*\frac{1L}{1000mL} = 0.250L$

Now divide the mol by the L.

$\frac{0.588mol NaNO3}{0.250L} = 2.352 M$

Round to the smallest number of significant figures = 2.35M