please help 100 points!!! will give crown to best answer if f(x) = 3x^2 -2x + 4 and g (x) = 5x ^2 + 6x -8 find (f-g) (x)

2 answers:

8 0

(f-g)(x) will be 3x^2 -2x+4 -(5x^2+6×-8)
distribute the -sign, gives us
3x^2-2x+4-5x^2-6x+8,
now combine like terms and should get,
-2x^2-8x+12,
final answer,
(f-g)(x)= -2x^2-8x+1×,
hope it helped,
good luck

koban [17]4 years ago

5 0

F(x) - g(x). We will subtract the terms and negate everything on the g(x) side as it is subtraction. We get 3x^2 - 2x +4 -5x^2 -6x +8 which equals -2x^2 +6x +12

You might be interested in

What is the the answer to 6/12 x2/3

mr_godi [17]

To multiply two fractions together, multiply the numerators of both fractions together and same goes for the denominators.

$\frac{6}{12} * \frac{2}{3} = \frac{12}{36}$

Simplify.

$\frac{12}{36} = \frac{1}{3}$

So, 1/3 is the answer.

6 0

3 years ago

What are the solutions to the equation x2 + 3 = 124? A. –3 and 3 B. –11 and 11 C. The equation has no solutions. D. –10

Ronch [10]

$x^2 + 3 = 124 \ \ |-124\\ \\x^2+3-124 = 124 -124 \\ \\ x^2-121 =0\\ \\x^2-11^2=0 \\ \\ (x-11)(x+11)=0\\ \\x-11=0 \ \ or \ \ x+11 =0\\ \\x=11 \ \ or \ \ x=-11 \\ \\Answer : B. \ \ -11 \ and \ \ 11 \\ \\ \\ a^2-b^2=(a-b)(a+b) 
$

3 0

4 years ago

The souvenir stand sells the hats for $11.75 each , the postcards for $0.25 each , and the magnets for $3.50 each . Write an exp

Anit [1.1K]

Answer:

9.2h+50

Step-by-step explanation:

im not sure if this is correct and im only in middle school but i had this same quetsion and got that snwer

5 0

3 years ago

Hehehejdjkskjsknssnnsnajsbsb

N76 [4]

Answer:

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

If x^2 +x-12 is a factor of x^3+ax^2-10x-b then find the values of a and b

Marysya12 [62]

Answer:

a=3

b=24

Step-by-step explanation:

If $x^2+x-12$ is a factor of $x^3+ax^2-10x-b$ , then the factors of $x^2+x-12$ must also be factors of $x^3+ax^2-10x-b$ .

So what are the factors of $x^2+x-12$ ? Well the cool thing here is the coefficient of $x^2[tex] is 1 so all we have to look for are two numbers that multiply to be -12 and add to be positive 1 which in this case is 4 and -3.-12=4(-3) while 1=4+(-3).So the factored form of [tex]x^2+x-12$ is $(x+4)(x-3)$ .