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DochEvi [55]
3 years ago
7

Find 38% of the number 405. a. 153.9% c. 1065.79 b. 153.9 d. 15,390

Mathematics
1 answer:
vredina [299]3 years ago
3 0
A.) 153.9 would be your answer!<span>
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the absolute value of -19 is 19 because the is the "real number" of -19

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Which value for x makes the sentence true?
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The answer is D. x=5
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What is 4 times 4 to the second power
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Assuming it is (4x4)^2, it is 64.

Step-by-step explanation:

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Stella graphs the equation y=1/3x – 2
faltersainse [42]

we have

y=\frac{1}{3}x-2

<u>Statements</u>

<u>case A)</u> The graph is a straight line.

The statement is True

Because, this is a linear equation (see the attached figure)

<u>case B)</u> The line passes through the origin.

The statement is False

Because the point (0,0) is not a solution of the equation

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Substitute the value of x and y in the equation

0=\frac{1}{3}*0-2

0=-2 ------> is not true

the point (0,0) is not a solution

therefore

The line does not pass through the origin

<u>case C)</u> The line passes through the point  (0,-2)

The statement is True

Because the point (0,-2) is a solution of the equation

Verify

Substitute the value of x and y in the equation

-2=\frac{1}{3}*0-2

-2=-2 ------> is true

the point (0,-2) is a solution

therefore

The line passes through the point (0,-2)

<u>case D) </u>The slope of the line is 3

The statement is False

Because, the slope of the line is m=\frac{1}{3}

<u>case E)</u> The y-intercept of the line is 2

The statement is False

we know that

The y-intercept is the value of y when the value of x is equal to zero

so

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5 0
3 years ago
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Translate into an algebraic expression: n−1 increased by 110%
lorasvet [3.4K]

Answer:

Part 1) The algebraic expression is equal to 1.10(n-1)  or 1.10n-1.10

Part 2) The algebraic expression is equal to \frac{1.10}{n}

Step-by-step explanation:

Part 1) we have (n-1) increased by 110%

110%=110/100=1.10

so

The algebraic expression of (n-1) increased by 110% is equal to multiply 1.10 by (n-1)

1.10(n-1)

Distributed

1.10n-1.10

Part 2) we have n^(-1) increased by 110%

110%=110/100=1.10

so

The algebraic expression of n^(-1) increased by 110% is equal to multiply 1.10 by n^(-1)

Remember that

n^{-1}=\frac{1}{n}

so

1.10(n^{-1})=1.10\frac{1}{n}=\frac{1.10}{n}

4 0
3 years ago
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