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Naily [24]
3 years ago
5

Which function has no horizontal asymptote?

Mathematics
2 answers:
Ivanshal [37]3 years ago
8 0

Function has no horizontal asymptote is C) f(x)=2x^2/3x-1

<h3>Further explanation </h3>

The rational functions graphs can be recognised by the fact that they often  break into two or more parts. These parts go out of the coordinate system along an imaginary straight line called an asymptote.

Vertical asymptotes can be found by solve the equation n(x) = 0, where n(x) is the function denominator. This only applies if the numerator t(x) is not zero for the same x value. The graph has a vertical asymptote with the equation x = 1.

The three rules that horizontal asymptotes are based on the degree of the numerator, n, and the degree of the denominator, m.

  • If n < m, the horizontal asymptote is y = 0.
  • If n = m, the horizontal asymptote is y = a/b.
  • If n > m, there is no horizontal asymptote.

A rational function has no horizontal asymptote when the degree of the numerator is greater than the denominator.

  • A) f(x)=2x-1/3x^2,  the degree of the numerator is lower than the denominator.
  • B) f(x)=x-1/3x,  the degree of the numerator is lower than the denominator.
  • C) f(x)=2x^2/3x-1 , the degree of the numerator is greater than the denominator.
  • D)f(x)=3x^2/x^2-1 , the degree of the numerator is lower than the denominator.
<h3 /><h3>Learn more</h3>
  1. Learn more about asymptote brainly.com/question/2914025
  2. Learn more about function brainly.com/question/12397187
  3. Learn more about horizontal asymptote brainly.com/question/4221615

<h3>Answer details</h3>

Grade:  9

Subject:  mathematics

Chapter:  Graphs of rational functions

Keywords: asymptote, function, horizontal asymptote, horizontal, mathematics

xxMikexx [17]3 years ago
3 0
A rational function has no horizontal asymptote when the degree of the numerator is greater than the denominator.

In other words, where the numerator has a higher exponent than the denominator.

Answer:
C)  exponent on top is 2, exponent on bottom is 1


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3, and -3

Step-by-step explanation:

Because absolute value is the distance away from zero, |3| and |-3| would both be 3 units away from 0. Be sure to have the negative on the inside if you're trying to make something positive, otherwise -|3| means that the absolute value of 3 would then become negative since the negative sign isn't a part of the absolute. hope this helps!

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3 years ago
Secant TP and tangent TR intersect at point 7. Chord SR and chord PQ intersect
prisoha [69]

Answer:

(C)x=11.6, y=23.2

Step-by-step explanation:

Using Theorem of Intersecting Secant and Tangent

Applying this theorem in the diagram, we have:

TQ$ X TP=TR^2

10(10+x+4)=16^2\\10(14+x)=256\\140+10x=256\\10x=256-140\\10x=116\\$Divide both sides by 10\\x=11.6

Next, we apply Theorem of Intersecting Chords

PV X VQ=SV X VR

4 X x= 2 X y

Recall earlier we got: x=11.6

2y=4 X 11.6

2y=46.4

Divide both sides by 2

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What is 66×94÷996-9 Please answer quicly
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3 years ago
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What is the length of the hypotenuse? If necessary, round to the nearest tenth.
Diano4ka-milaya [45]

<u>Answer:</u>

  • The value of c is 2√2 or about 2.8.

<u>Step-by-step explanation:</u>

<u>We can find the hypotenuse (c) with the help of Pythagoras Theorem.</u>

  • => c² = 2² + 2²
  • => c² = 4 + 4
  • => c² = 8
  • => c = √8
  • => c = √2 x 2 x 2
  • => c = 2√2

<u>If you want further simplification, seek for explanation below.</u>

  • => c = 2√2
  • => c = 2 x √2
  • => c = 2 x 1.414
  • => c = 2.828 = 2.8 (Estimated)

Hence, <u>the value of c is 2√2 or about 2.8.</u>

Hoped this helped.

BrainiacUser1357

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