Answer:
D
Step-by-step explanation:
So you can protect your eyes.
<span><span> 17
</span><span>2 35
</span> 2
<span> 15
</span><span> 14
</span><span> 1
The remainder ends up to be 1. So it is 17.5. All you need to do, is to look for LCM in 35 and 2. </span></span>
Answer:
Step-by-step explanation:
Given that
sample size n = 55: x bar = 654.16 and s = sample sd = 162.34
Std error = 162.34/sqrt 55 = 21.889
For 95% CI we can use t critical value as population std dev is not known.
df = 54
t critical = 2.004
Margin of error = 2.004 *21.889 = 43.866
Confidence interval lower bound = 654.16-43.866 =610.294
Upper bound = 654.16+43.866=698.026
Confidence interval rounded off at 95% = (610.29, 698.23)
To answer this question you can create an equation in terms of the number of zucchini that were planted. Each other plant gives information that can relate to the number of zucchini plants.
# of cucumbers + # of tomatoes + # of zucchini
2z + 2z + 8 + z = 43
5z + 8 = 43
-8 -8
<u>5z</u> = <u>35</u>
5 5
z = 7 plants
There were 7 zucchini plants, 14 (2 x 7) cucumber plants, and 22 (2 x 7 + 8) tomato plants.
Answer:
2^5 or 32
Step-by-step explanation:
