The coordinates of the endpoints of line segments T'V' are; T'(-1, 2) and V'(0, 1).
<h3>What are the coordinates of the endpoints of the segment T'V'?</h3>
It follows from the task content that the transformation involved in the formation of the image from the pre-image is dilation by a scale factor of 1/4.
On this note, given that the coordinates of T and V from the task content are; (-4, 8) and (0,4), it follows that the coordinates of the endpoints as required are; T'(-1, 2) and V'(0, 1).
Read more on dilations;
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B
First you have to change 2 1/2 into 5/2
To multiply fractions use the method
Keep Change Flip
5/2 x 3/1 =15/2
Which simplifies to 7 1/2
Shade 3 bars and you'll get it right
Answer: (C) shifts 6 units to the LEFT
<u>Step-by-step explanation:</u>
The vertex form of an absolute value equation is:
y = a |x - h| + k where;
- a is the vertical stretch (irrelevant for this problem)
- (h, k) is the vertex
Since h represents the x-coordinate and the x-axis is left to right, then h shifts the graph left or right.
- If h is negative, the graph shifts to the left.
- If h is positive, the graph shifts to the right.
x + 6 is actually x - (-6), so h is negative and the graph shifts to the left.
We know that the volume of a rectangular prism is given by:
V = A · h
where:
A = surface area
h = height
Therefore, you can solve for A:
A = V / h
= 64 / h
Now, you need to ask yourself by how many numbers you can divide 64. The possible heights are 64, 32, 16, 8, 4, 2 and 1.
Hence:
A) there are 7 possible surface areas (one for each possible height).
B) the <span>maximum Area will be that of the box with the minimum height:
A = 64 / 1 = 64
C) the minimum Area will be that of the box with the maximum height:
A = 64 / 64 = 1</span>
