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KatRina [158]
3 years ago
11

An aluminum can of a soft drink is placed in a freezer. later, you find that the can is split open and its contents frozen. work

was done on the can in splitting it open.
Chemistry
1 answer:
katen-ka-za [31]3 years ago
5 0
This is a true statement, if thats your inquiry.
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What is the molar mass off a substance?
ruslelena [56]
It is the mass of one mole of the substance.
4 0
3 years ago
Calculate the MASS if the density is 2.34 g/mL and the volume is 12.50 mL.
AlexFokin [52]

Answer:

<h2>mass = 29.25 g</h2>

Explanation:

The denisty of a substance can be found by using the formula

Density =  \frac{mass}{volume}

Making mass the subject we have

<h3>mass = Density × volume</h3>

From the question

Density = 2.34 g/mL

volume = 12.50 mL

Substitute the values into the above formula and solve for the mass

That's

mass = 2.34 × 12.50

We have the final answer as

<h3>mass = 29.25 g</h3>

Hope this helps you

3 0
3 years ago
What is one differrence between a mixture and a compound
Ann [662]

Answer:

A mixture can contain components in any proportions while a compound contains components in fixed proportions. All components in a mixture do not chemically react, while the components in a compound do react and their original properties are lost.

3 0
3 years ago
If 3.49 g of silver chloride, AgCl, is produced from the reaction of 5.95 g AgNO3 with excess BaCl2,
TEA [102]

Answer:

that not of i grade sorry

Explanation:

3 0
3 years ago
How much heat is required to raise the temperature of 225 grams of ice from -26.8 °C to steam at 133 °C ?
lara [203]
<h3>Answer:</h3>

150000 J

<h3>General Formulas and Concepts:</h3>

<u>Chemistry</u>

<u>Thermodynamics</u>

Specific Heat Formula: q = mcΔT

  • <em>q</em> is heat (in J)
  • <em>m</em> is mass (in g)
  • <em>c</em> is specific heat (in J/g °C)
  • ΔT is change in temperature (in °C or K)

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right
<h3>Explanation:</h3>

<u>Step 1: Define</u>

<em>Identify variables</em>

[Given] <em>m</em> = 225 g

[Given] <em>c</em> = 4.184 J/g °C

[Given] ΔT = 133 °C - -26.8 °C = 159.8 °C

[Solve] <em>q</em>

<u>Step 2: Solve for </u><em><u>q</u></em>

  1. Substitute in variables [Specific Heat Formula]:                                          q = (225 g)(4.184 J/g °C)(159.8 °C)
  2. Multiply:                                                                                                           q = (941.4 J/°C)(159.8 °C)
  3. Multiply:                                                                                                           q = 150436 J

<u>Step 3: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

150436 J ≈ 150000 J

Topic: AP Chemistry

Unit: Thermodynamics

Book: Pearson AP Chemistry

5 0
3 years ago
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