there's no picture here but I guess the answer would be:
considering the constant temperature, if you double the volume, the pressure would be halved.
like: volume is 2, pressure is 4
if 2×2, then:4÷2
B. Low blood pressure and drooling. If the user is tranquilized, he would not be able to hinder the production of saliva, leading to drooling. And if the victim was tranquilized, his heart would slow down, not speed up, resulting in a lower blood pressure.
The enthalpy change : -196.2 kJ/mol
<h3>Further explanation </h3>
The change in enthalpy in the formation of 1 mole of the elements is called enthalpy of formation
The enthalpy of formation measured in standard conditions (25 ° C, 1 atm) is called the standard enthalpy of formation (ΔHf °)
(ΔH) can be positive (endothermic = requires heat) or negative (exothermic = releasing heat)
The value of ° H ° can be calculated from the change in enthalpy of standard formation:
∆H ° rxn = ∑n ∆Hf ° (product) - ∑n ∆Hf ° (reactants)
Reaction
2 H₂O₂(l)-→ 2 H₂O(l) + O₂(g)
∆H ° rxn = 2. ∆Hf ° H₂O - 2. ∆Hf °H₂O₂
