The periodic table is based on an element's

Guillaume Amontons first took a stab at measuring absolute zero in 1702. What would be the most reasonable way it would have bee

Tema [17]

The most reasonable way to measure absolute zero would have been to extrapolate the ideal gas law.

<h3>What is Absolute zero?</h3>

This is referred to the temperature at which a thermodynamic system has the lowest form of energy.

Guillaume Amontons used gas equation to prove that absence of heat was theoretically possible which would have involved only extrapolating the ideal gas law.

Read more about Absolute zero here brainly.com/question/18560146

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3 0

2 years ago

A bulldozer does 15,000 J of work lifting dirt 15 m up to get it out of a hole. How much force did the bulldozer use to accompli

nika2105 [10]

Answer:

<h3>The answer is 3000 N</h3>

Explanation:

The amount of force can be found by using the formula

$f = \frac{w}{d} \\$

w is the workdone

d is the distance

From the question we have

$f = \frac{15000}{5} \\$

We have the final answer as

Hope this helps you

7 0

2 years ago

How many litres of 15% (mass/ volume) copper sulphate solution

givi [52]

Take 15/100 X 75 = The answer

4 0

3 years ago

Read 2 more answers

How much faster does helium escape through a porous container than ozone?

otez555 [7]

According to Graham's Law ," the rates of effusion or diffusion of two gases are inversely proportional to the square root of their molecular masses at given pressure and temperature".

r₁ / r₂ =   $\sqrt{M2 / M1}$ ---- (1)

r₁ = Rate of effusion of He

r₂ = Rate of Effusion of O₃

M₁ = Molecular Mass of He = 4 g/mol

M₂ = Molecular Mass of O₃ = 48 g/mol

Putting values in eq. 1,

r₁ / r₂ =   $\sqrt{48 / 4}$

r₁ / r₂ =   $\sqrt{12}$

r₁ / r₂ = 3.46

Result:
Therefore, Helium will effuse 3.46 times more faster than Ozone.

4 0

3 years ago

what is the percent yield of titanium (II) oxide if 20.0 grams of titanium (II) sulfide is reacted with water? The actual yield

earnstyle [38]

Answer : The percent yield of titanium (II) oxide is, 142.5 % and the impurities could have caused the percent yield to be so high.

Explanation : Given,

Mass of titanium(II) sulfide = 20.0 g

Molar mass of titanium(II) sulfide = 79.9 g/mole

Molar mass of titanium(II) oxide = 63.9 g/mole

First we have to calculate the moles of titanium(II) sulfide.

$\text{ Moles of titanium(II) sulfide}=\frac{\text{ Mass of titanium(II) sulfide}}{\text{ Molar mass of titanium(II) sulfide}}=\frac{20.0g}{79.9g/mole}=0.2503moles$

Now we have to calculate the moles of titanium(II) oxide.

The balanced chemical reaction is,

$TiS+H_2O\rightarrow TiO+H_2S$

From the reaction, we conclude that

As, 1 mole of titanium(II) sulfide react to give 1 mole of titanium(II) oxide

So, 0.2503 mole of titanium(II) sulfide react to give 0.2503 mole of titanium(II) oxide

Now we have to calculate the mass of titanium(II) oxide.

$\text{ Mass of titanium(II) oxide}=\text{ Moles of titanium(II) oxide}\times \text{ Molar mass of titanium(II) oxide}$

$\text{ Mass of titanium(II) oxide}=(0.2503moles)\times (63.9g/mole)=15.99g$

To calculate the percentage yield of titanium (II) oxide, we use the equation:

$\%\text{ yield}=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100$

Experimental yield of titanium (II) oxide = 22.8 g

Theoretical yield of titanium (II) oxide = 15.99 g

Putting values in above equation, we get:

$\%\text{ yield of titanium (II) oxide}=\frac{22.8g}{15.99g}\times 100\\\\\% \text{yield of titanium (II) oxide}=142.5\%$

Hence, the percent yield of titanium (II) oxide is, 142.5 %

If the percent yields is greater than 100% that means the product of the reaction contains impurities which cause its mass to be greater than it actually.

5 0

3 years ago