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ASHA 777 [7]
2 years ago
10

How are monosaccharides different from disaccharides?

Chemistry
2 answers:
Elis [28]2 years ago
5 0

Answer:

A. ) Monosaccharides are the simplest carbohydrates. Disaccharides are made up of two monosaccharides.

Explanation:

Monosaccharides serve as carbohydrate monomers; disaccharides are simply two monosaccharide units bonded together.

FrozenT [24]2 years ago
4 0

Answer:

A

Explanation:

edge 2021

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You are running a rather large scale reaction where you prepare the grignard reagent phenylmagnesium bromide by reacting 210.14
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Answer:

We would expect to form 7.35 moles of grignard reagent.

Explanation:

<u>Step 1: </u>Data given

Mass of magnesium = 210.14 grams

Volume bromobenzene = 772 mL

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Molar mass of Mg = 24.3 g/mol

Molar mass of bromobenzene = 157.01 g/mol

<u>Step 2</u>: The balanced equation

C6H5Br + Mg ⇒ C6H5MgBr

<u>Step 3:</u> Calculate mass of bromobenzene

Mass bromobenzene = density bromobenzene * volume

Mass bromobenzene = 1.495 g/mL * 772 mL

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<u>Step 4</u>: Calculate number of moles bromobenzene

Moles bromobenzene = mass bromobenzene / molar mass bromobenzene

Moles bromobenzene = 1154.14g / 157.01 g/mol

Moles bromobenzene = 7.35 moles

<u>Step 5:</u> Calculate moles of Mg

Moles Mg = 210.14 grams /24.3 g/mol

Moles Mg = 8.65 moles

<u>Step 6:</u> The limiting reactant

The mole ratio is 1:1 So the bromobenzene has the smallest amount of moles, so it's the limiting reactant. It will be completely consumed ( 7.35 moles). Magnesium is in excess, There will react 7.35 moles. There will remain 8.65 - 7.35 = 1.30 moles

<u>Step 7:</u> Calculate moles of phenylmagnesium bromide

For 1 mole of bromobenzene, we need 1 mole of Mg to produce 1 mole of phenylmagnesium bromide

For 7.35 moles bromobenzene, we have 7.35 moles phenylmagnesium bromide

We would expect to form 7.35 moles of grignard reagent.

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