Answer:
The answer to your question is 35.4527 g
Explanation:
Data
Cl-35 abundance = 75.77 % mass Cl-35 = 34.9688
Cl-37 abundance = 24.23 % mass Cl-37 = 36.9659
Process
1.- Convert the percents to decimals
75.77% = 75.77/100 = 0.7577
24.23% = 24.23/100 = 0.2423
2.- Find the atomic weight
Average atomic weight = Abundance 1 x Mass Cl-35 +
Abundance 2 x Mass Cl-37
Substitution
Average atomic weight = (0.7577)(34.9688) + (0.2423 x 36.9659)
Simplification
Average atomic weight = 26.4959 + 8.9568
Result
Average atomic weight = 35.4527 g
steps...
1) convert mass H2O to moles H2O
2) use coefficients of balanced equation to convert to moles O2
3) convert moles O2 to L O2.
solution...
10.5 g H2O x (1 mole H2O / 18.0 g H2O) = 0.583 moles H2O
from the balanced equation, 1 mole O2 --> 2 moles H2O.. therefore...
0.583 moles H2O x (1 mole O2 / 2 moles H2O) = 0.292 moles O2
from here you can either use the specific form of the ideal gas law for STP...
0.292 moles O2 x (22.4 L O2 / mole O2) = 6.54 L O2
or you can use the more general form of the ideal gas law...
V = nRT/P = (0.292 moles) x (0.0821 Latm/moleK) x (273 K) / (1 atm)
V = 6.54 L O2
Hope this helps!
Answer:
well it is because of mainly what we call reaction the petrol are highly reactive with the flames
Dmitri Mendeleev, he realized that the physical and chemical properties of elements were related to their atomic mass and arranged them into groups (columns)
