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HACTEHA [7]
3 years ago
14

Uranium is used in nuclear reactors and is a rare element on earth. Uranium has three common isotopes. If the abundance of 234U

is 0.01% the abundance of 235U is 0.71% and the abundance of 238U is 99.28% what is the average atomic mass of uranium
Chemistry
1 answer:
LenaWriter [7]3 years ago
3 0

Answer:

Average atomic mass of uranium= 237.98 amu.

Explanation:

Given data:

Abundance of U²³⁴ = 0.01%

Abundance of U²³⁵ = 0.17%

Abundance of U²³⁸ = 99.28%

Average atomic mass = ?

Solution:

Average atomic mass of uranium = (abundance of 1st isotope × its atomic mass) +(abundance of 2nd isotope × its atomic mass) +(abundance of 3rd isotope × its atomic mass) / 100

Average atomic mass of uranium= (234×0.01)+(235×0.71)+(238×99.28)/100

Average atomic mass of uranium=  2.34 + 166.85 + 23628.64 / 100

Average atomic mass of uranium= 23797.83 / 100

Average atomic mass of uranium= 237.98 amu.

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The number of years that must be invested at  a rate of 7 % to earn$ 303.52 in interest is

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 <em><u>calculation</u></em>

  • <em><u> </u></em><em>by use of  the formula       A = P (1+  rt) </em>
  • <em>  where :  A  is the final amount  =  542 + 303.52  =$ 845.52</em>

<em>                    P  is the principal   money to be invested =  $ 542</em>

<em>                        r= rate= 7/100=0.07</em>

<em>                       t=  time required</em>

<em>=$ 845.52=$ 542( 1+  0.07 t)</em>

  • <em>open the  bracket</em>
  • <em>= $845.53= $542 + $37.94  t</em>

  • <em>like terms  together</em>

    =$  845.53 -$542  = $37.94 t

   =$303.52 =$37.94 t

  • divide both  side by  $37.94

  =  $303.52/ $   37.94  =  $37.94t/$37.94

  t=  8 years

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2 years ago
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