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Advocard [28]
2 years ago
6

Which describe beta decay? check all that apply. in beta decay, a proton becomes a neutron and a positron. in beta decay, a neut

ron becomes a proton and an electron. in beta decay, a neutron becomes a proton and a gamma ray. beta decay releases energy. beta decay releases a helium-4 nucleus.
Chemistry
1 answer:
kiruha [24]2 years ago
6 0

The statements which best describe beta decay are: option 1, 2 and 4.

<h3>What is a beta particle?</h3>

A beta particle can be defined as an isotope which typically undergoes radioactive decay through the emission of a radiation with a -1 charge.

Based on scientific information and records from radioactivity, we can infer that the statements which best describe beta decay are:

  • During beta decay, an atom of proton becomes a neutron and a positron.
  • During beta decay, an atom of neutron becomes a proton and an electron.
  • Beta decay releases energy.

Read more on beta decay here: brainly.com/question/12448836

#SPJ4

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Butane C4H10 (g),(Hf = –125.7), combusts in the presence of oxygen to form CO2 (g) (Delta.Hf = –393.5 kJ/mol), and H2O(g) (Delta
shusha [124]

Answer: The enthalpy of combustion, per mole, of butane is -2657.4 kJ

Explanation:

The balanced chemical reaction is,

2C_4H_{10}(g)+13O_2(g)\rightarrow 8CO_2(g)+10H_2O(g)

The expression for enthalpy change is,

\Delta H=[n\times H_f_{products}]-[n\times H_f_{reactants}]

Putting the values we get :

\Delta H=[8\times H_f_{CO_2}+10\times H_f_{H_2O}]-[2\times H_f_{C_4H_{10}+13\times H_f_{O_2}}]

\Delta H=[(8\times -393.5)+(10\times -241.82)]-[(2\times -125.7)+(13\times 0)]

\Delta H=-5314.8kJ

2 moles of butane releases heat = 5314.8 kJ

1 mole of butane release heat = \frac{5314.8}{2}\times 1=2657.4kJ

Thus enthalpy of combustion per mole of butane is -2657.4 kJ

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A student is titrating 50 mL of 0.32 M NH3 with 0.5 M HCl. How much hydrochloric acid must be added to react completely with the
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The volume of HCl to be added to completely react with the ammonia is 0.032 L or 32mL

Explanation:

Using the formula

Ca Va = Cb Vb

Cb = 0.32 M

Vb = 50 mL = 50/1000 = 0.050L

Ca = 0.5 M

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Substituting for Va in the equation, we obtain:

Va = Cb Vb / Ca

Va = 0.32 * 0.05 / 0.5

Va = 0.016 / 0.5

Va = 0.032 L

The volume of HCl to be added to completely react with the ammonia is 0.032 L or 32mL

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