Answer:
what is flowing in physical?
Explanation:
Answer:
Option D - 0.2 s
Explanation:
We are given;
Initial velocity; u = 7 m/s
Height of table; h = 1.8m
Now,since we want to find the time the car spent in the air, we will simply use one of Newton's equation of motion.
Thus;
h = ut + ½gt²
Plugging in the relevant values, we have;
1.8 = 7t + ½(9.8)t²
4.9t² + 7t - 1.8 = 0
Using quadratic formula to find the roots of the equation gives us;
t = -1.65 or 0.22
We can't have negative t value, thus we will pick the positive one.
So, t = 0.22 s
This is approximately 0.2 s
(a) The frequency of the motion after the collision is 0.71 Hz.
(b) The maximum angular displacement of the motion after the collision is 16.3⁰.
<h3>Speed of the 2.2 kg ball when it collides with 2.7 kg ball</h3>
The speed of the 2.2 kg ball which was initially 10 cm higher that 2.7 kg ball is calculated as follows;
K.E = P.E
¹/₂mv² = mgh
v² = 2gh
v = √2gh
v = √(2 x 9.8 x 0.1)
v = 1.4 m/s
<h3>Final speed of both balls after collision</h3>
The final speed of both balls after the collision is determined from the principle of conservation of linear momentum.
Pi = Pf
m₁v₁ + m₂v₂ = vf(m₁ + m₂)
2.2(1.4) + 2.7(0) = vf(2.2 + 2.7)
3.08 = 4.9vf
vf = 3.08/4.9
vf = 0.63 m/s
<h3>Maximum displacement of the balls after the collision</h3>
P.E = K.E
![mgh_f = \frac{1}{2} mv_f^2\\\\h_f = \frac{v_f^2}{2g} \\\\h_f = \frac{(0.63)^2}{2(9.8)} \\\\h_f = 0.02 \ m](https://tex.z-dn.net/?f=mgh_f%20%3D%20%5Cfrac%7B1%7D%7B2%7D%20mv_f%5E2%5C%5C%5C%5Ch_f%20%3D%20%5Cfrac%7Bv_f%5E2%7D%7B2g%7D%20%5C%5C%5C%5Ch_f%20%3D%20%5Cfrac%7B%280.63%29%5E2%7D%7B2%289.8%29%7D%20%5C%5C%5C%5Ch_f%20%3D%200.02%20%5C%20m)
<h3>Maximum angular displacement</h3>
The maximum angular displacement of the balls after the collision is calculated as follows;
![cos \theta = \frac{L - h_f}{L} \\\\cos\theta = \frac{0.5 - 0.02}{0.5} \\\\cos\theta = 0.96\\\\\theta = cos^{-1}(0.96)\\\\\theta = 16.3 \ ^0](https://tex.z-dn.net/?f=cos%20%5Ctheta%20%3D%20%5Cfrac%7BL%20-%20h_f%7D%7BL%7D%20%5C%5C%5C%5Ccos%5Ctheta%20%3D%20%5Cfrac%7B0.5%20-%200.02%7D%7B0.5%7D%20%5C%5C%5C%5Ccos%5Ctheta%20%3D%200.96%5C%5C%5C%5C%5Ctheta%20%3D%20cos%5E%7B-1%7D%280.96%29%5C%5C%5C%5C%5Ctheta%20%3D%2016.3%20%5C%20%5E0)
<h3>Frequency of the motion</h3>
![f = \frac{1}{2\pi} \sqrt{\frac{g}{L} } \\\\f = \frac{1}{2\pi } \sqrt{\frac{9.8}{0.5} } \\\\f = 0.71 \ Hz](https://tex.z-dn.net/?f=f%20%3D%20%5Cfrac%7B1%7D%7B2%5Cpi%7D%20%5Csqrt%7B%5Cfrac%7Bg%7D%7BL%7D%20%7D%20%5C%5C%5C%5Cf%20%3D%20%5Cfrac%7B1%7D%7B2%5Cpi%20%7D%20%5Csqrt%7B%5Cfrac%7B9.8%7D%7B0.5%7D%20%7D%20%5C%5C%5C%5Cf%20%3D%200.71%20%5C%20Hz)
Learn more about maximum angular displacement here: brainly.com/question/13665036
It would be a really bad idea to eat the snow because you obviously are trying to stay warm right? Well, the best thing to do is melt the snow. However, the process of melting the snow would have a few complications as well. But yes, the latter idea (drinking the snow) is a better idea (not the best).