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tamaranim1 [39]

3 years ago

11

The dogs of four-time Iditarod Trail Sled Dog Race champion Jeff King pull two 100-kg sleds that are connected by a rope. The sl

eds move on an icy surface. The dogs exert a 240-N force on the rope attached to the front sled. The front rope pulls horizontally.
Part A
Find the acceleration of the sleds.
Express your answer to two significant figures and include the appropriate units.
Part B
Find the force the rope between the sleds exerts on each sled.
Express your answer to two significant figures and include the appropriate units.

2 answers:

azamat3 years ago

7 0

Answer:

Part a)

$a = 2.4 m/s^2$

Part b)

$F = 120 N$

Explanation:

Two sleds are connected by a rope

mass of each sled is given as

$m = 100 kg$

now we know that dog exert pulling force on the rope connected to first sled

$F = 240 N$

Part a)

By newton's first law we know that

$F = (m + m)a$

$240 = (100 + 100)a$

$a = \frac{240}{100}$

$a = 2.4 m/s^2$

Part b)

As we know that force between two ropes will pull the sled behind

so we will have

$F = ma$

$F = 100(1.20)$

$F = 120 N$

loris [4]3 years ago

5 0

Answer:

Answer:

(a) acceleration a = 1.2m/s2

(b) force F = 100N on each sled

Explanation:

The explanation is in the attached file below

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Four identical capacitors are connected with a resistor in two different ways. When they are connected as in part a of the drawi

Nina [5.8K]

Answer:

$T_2 = 0.592$

Explanation:

Given

$T_1 = 1.48s$

See attachment for connection

Required

Determine the time constant in (b)

First, we calculate the total capacitance (C1) in (a):

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Both (a) and (b) have the same resistance.

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We have:

Time constant is directional proportional to capacitance:

So:

$T\ \alpha\ C$

Convert to equation

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Make k the subject

$k = \frac{T}{C}$

$k = \frac{T_1}{C_1} = \frac{T_2}{C_2}$

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Substitute values for T1, C1 and C2

$T_2 = \frac{1.48 * \frac{2}{5}C}{C}$

$T_2 = \frac{1.48 * \frac{2}{5}}{1}$

$T_2 = \frac{0.592}{1}$

$T_2 = 0.592$

Hence, the time constance of (b) is 0.592 s

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