Ask question

Ask question

All categories

ludmilkaskok [199]

3 years ago

13

A battery supplies 0.75 A to three resistors connected in parallel. The current through the first resistor is 0.24 A and the cur

rent through the second resistor is 0.22
a. What is the exact current (in
a. through the third resistor? Do not include units with your answer.

1 answer:

Anastasy [175]3 years ago

7 0

Total current flow in circuit=0.75
Current flow through third resistor=0.75-(0.24+0.22)
=0.29

You might be interested in

As speed increases, how does the potential, kinetic, and total energy levels change?

Anastaziya [24]

Potential equals kenecric at the bottom so potential would also increas

4 0

3 years ago

Lucas left a metal bowl and a wooden bowl outside overnight. The next morning, he picked up the bowls to bring them inside. He n

kipiarov [429]

Answer: C. Metal transfers heat away from the skin by conduction, creating the sensation of coolness.

Explanation: The skin releases heat into the metal bowl since there is a difference in temperature between the two objects. So heat is taken away from the hand abd transfers into the metal bowl by conduction creating a cooler sensation.

8 0

3 years ago

Which of the following types of pollution is NOT linked to coal-burning power plant emissions?

Vika [28.1K]

A is not linked. Coal burning is not an effect of acid rain.
~Deceptiøn

8 0

3 years ago

One type of cold remedy is an effervescent tablet that breaks down in water. When the tablet is placed in water, it forms gas bu

oksano4ka [1.4K]

Answer:

is a sign of a chemical change

Explanation:

The tablet reacts with the water to form carbon dioxide

7 0

3 years ago

Read 2 more answers

A child\'s top is held in place, upright on a frictionless surface. The axle has a radius of r = 2.96 mm. Two strings are wrappe

sladkih [1.3K]

Answer:

Explanation:

Given

radius r=2.96 mm

Tension T=2.4 N

time taken=0.74 s

Let $\alpha$ be the angular acceleration

$2 T\times r=I\times \alpha$

$2\times 2.4\times 2.96\times 10^{-3}=0.5\times m\times (2.96\times 10^{-3})^2\times \alpha$

$\alpha =\frac{4\times 2.4}{m\times 2.96\times 10^{-3}}$

$\alpha =\frac{3.24\times 10^3}{m} rad/s^2$

$\omega =\omega _0+\alpha \cdot t$

$\omega =0+\frac{3.24\times 10^3}{m}\times 0.74$

$\omega =\frac{2.4\times 10^3}{m} rad/s$

Angular momentum

$L=I\omega$

$L=0.5\times mr^2\times \omega$

$L=0.5\times m\times (2.96\times 10^{-3})^2\times \frac{2.4\times 10^3}{m}$

$L=0.01051 kg-m^2/s$

4 0

3 years ago