Ask question

Ask question

All categories

ludmilkaskok [199]

3 years ago

13

A battery supplies 0.75 A to three resistors connected in parallel. The current through the first resistor is 0.24 A and the cur

rent through the second resistor is 0.22
a. What is the exact current (in
a. through the third resistor? Do not include units with your answer.

1 answer:

Anastasy [175]3 years ago

7 0

Total current flow in circuit=0.75
Current flow through third resistor=0.75-(0.24+0.22)
=0.29

You might be interested in

How is displacement different from distance?

Anni [7]

Answer:

i do belive its C

Explanation:

i remeber this question from somewhere also it makes the most sense

5 0

4 years ago

Read 2 more answers

Explain how a star's absorption spectrum and the concept of red shift help support the Big Bang Theory.

marta [7]

Answer:

Red shift supports the big bang theory. ... The light from distant galaxies is red shifted (this tells us the galaxies are moving away from us) and the further away the galaxy the greater the red shift (this tells us that the more distant the galaxy the faster it is moving). Constellations look like they are moving because earth is rotating on it's axis.

May I have brainliest, please?

4 0

3 years ago

Two large, plastic tubs were filled with soil The soil was shaped to create a mound in each tub. The starting height of each mou

shutvik [7]

Answer:

b

Explanation:

6 0

2 years ago

What is the wavelength of microwaves with a frequency of 3x10^10 Hz?

RUDIKE [14]

Answer:

0.01 m

Explanation:

Since the speed of light is 3.0×10^8 m/s

Use the equation,

Wavelength = speed ÷ frequency

Wavelength = 3.0×10^8 ÷ 3×10^10

Wavelength = 0.01m

5 0

3 years ago

Voltage needed to raise current to 3.75a using 20,20,200 resistor set

Varvara68 [4.7K]

<u>Answer:</u> The voltage needed is 35.7 V

<u>Explanation:</u>

Assuming that the resistors are arranged in parallel combination.

For the resistors arranged in parallel combination:

$\frac{1}{R}=\frac{1}{R_1}+\frac{1}{R_2}+\frac{1}{R_3}$

We are given:

$R_1=20\Omega\\R_2=20\Omega\\R_3=200\Omega$

Using above equation, we get:

$\frac{1}{R}=\frac{1}{20}+\frac{1}{20}+\frac{1}{200}\\\\\frac{1}{R}=\frac{10+10+1}{200}\\\\R=\frac{200}{21}=9.52\Omega$

Calculating the voltage by using Ohm's law:

$V=IR$ .....(1)

where,

V = voltage applied

I = Current = 3.75 A

R = Resistance = $9.52\Omega$

Putting values in equation 1, we get:

$V=3.75\times 9.52\\\\V=35.7V$

Hence, the voltage needed is 35.7 V

7 0

3 years ago

Read 2 more answers