Answer:
<h2>50m/s^2</h2>
Explanation:
Step one:
given data
initial velocity u= 0m/s since the ball is at rest
time of contact t= 0.3s
final velocity v=15m/s
Required
acceleration a
from the first law of motion
v=u+at
substitute our given data
15=0+a*0.3
15=0.3a
divide both sides by 0.3
a=15/0.3
a=50m/s
<u>The average acceleration is 50m/s^2</u>
The particle moves with constant speed in a circular path, so its acceleration vector always points toward the circle's center.
At time
, the acceleration vector has direction
such that

which indicates the particle is situated at a point on the lower left half of the circle, while at time
the acceleration has direction
such that

which indicates the particle lies on the upper left half of the circle.
Notice that
. That is, the measure of the major arc between the particle's positions at
and
is 270 degrees, which means that
is the time it takes for the particle to traverse 3/4 of the circular path, or 3/4 its period.
Recall that

where
is the radius of the circle and
is the period. We have

and the magnitude of the particle's acceleration toward the center of the circle is

So we find that the path has a radius
of

A nuclear particle with no charge is a neutron
Answer:
The magnetic flux through surface is
Wb
Explanation:
Given :
Magnitude of magnetic field
T
Radius of circle
m
Angle between field and surface normal
25°
From the formula of flux,


Where
angle between magnetic field line and surface normal,
area of circular surface.



Magnetic flux is given by,

Wb
Therefore, the magnetic flux through surface is
Wb
The continuious physical force per unit area that one region of a gas, liquid, or solid exerts on another.