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aleksandrvk [35]
3 years ago
15

How many millilitres are they in two and a quater litres

Mathematics
1 answer:
Bess [88]3 years ago
5 0
Mili means 1000 so 1000ml=1 L (ml=milileter, L=liter)
conversion factor
1L/1000ml=1 and
1000ml/1L=1
convert 2 and 1/4 L to ml
2 and 1/4L
try to convert with second conversion thing (1000ml/1L=1)
2 and 1/4L times 1000ml/1L=2000 and 1000/4 ml=2000 and 250 ml=2250 ml
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80 POINTS HELP<br> 1. What is the value of x? Show all of your work.
AnnyKZ [126]

Answer:

x = 9cm

Step-by-step explanation:

This is a right triangle so we can use the Pythagorean theorem

a^2 + b^2 = c^2  where a and b are the legs and c is the hypotenuse

6^2 + x^2 = ( sqrt(117) ^2)

36 + x^2 = 117

Subtract 36 from each side

x^2 = 117 -36

x^2 = 81

Take the square root of each side

sqrt(x^2) = sqrt(81)

x = 9

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3 years ago
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To save money, a local charity organization wants to target its mailing requests for donations to individuals who are most suppo
mars1129 [50]

Answer:

The 80% confidence interval for difference between two means is (0.85, 1.55).

Step-by-step explanation:

The (1 - <em>α</em>) % confidence interval for difference between two means is:

CI=(\bar x_{1}-\bar x_{2})\pm t_{\alpha/2,(n_{1}+n_{2}-2)}\times SE_{\bar x_{1}-\bar x_{2}}

Given:

\bar x_{1}=M_{1}=6.1\\\bar x_{2}=M_{2}=4.9\\SE_{\bar x_{1}-\bar x_{2}}=0.25

Confidence level = 80%

t_{\alpha/2, (n_{1}+n_{2}-2)}=t_{0.20/2, (5+5-2)}=t_{0.10,8}=1.397

*Use a <em>t</em>-table for the critical value.

Compute the 80% confidence interval for difference between two means as follows:

CI=(6.1-4.9)\pm 1.397\times 0.25\\=1.2\pm 0.34925\\=(0.85075, 1.54925)\\\approx(0.85, 1.55)

Thus, the 80% confidence interval for difference between two means is (0.85, 1.55).

3 0
3 years ago
Write a polynomial function of minimum degree with real coefficients whose zeros include those listed. Write the polynomial in s
wolverine [178]

Answer:

x^4 - 14x^2 - 40x - 75.

Step-by-step explanation:

As complex roots exist in conjugate pairs the other zero is -1 - 2i.

So in factor form we have the polynomial function:

(x - 5)(x + 3)(x - (-1 + 2i))(x - (-1 - 2i)

= (x - 5)(x + 3)( x + 1 - 2i)(x +1 + 2i)

The first 2 factors  = x^2 - 2x - 15 and

( x + 1 - 2i)(x +1 + 2i) = x^2 + x + 2ix + x + 1 + 2i - 2ix - 2i - 4 i^2

=  x^2 + 2x + 1 + 4

= x^2 + 2x + 5.

So in standard form we have:

(x^2 - 2x - 15 )(x^2 + 2x + 5)

= x^4  + 2x^3 + 5x^2 - 2x^3 - 4x^2 - 10x - 15x^2 - 30x - 75

= x^4 - 14x^2 - 40x - 75.

7 0
4 years ago
The measure of EFH is twice the measure of GFH. What is the
Vladimir [108]

Answer:

30° =  m∠GFH

Step-by-step explanation:

Since ∠EFH and ∠GFH are complementary, the sum of their measures i 90.

Let x = m∠GFH

2x = m∠EFH

m∠GFH + m∠EFH = 90

x + 2x = 90

3x = 90

x = 30° =  m∠GFH

8 0
3 years ago
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