3 years ago

Instrument panel help please

Engineering

1 answer:

nirvana33 [79]3 years ago

4 0

Answer:

A. 4WD Low

B. 4WD High

C. Safety belt

D. Check gauge

E. Oil temperature gauge

F. Left turn indicator

G. Tachometer

H. High beams

I. Speedometer

J. Right turn indicator

K. Battery voltage gauge

L. Cruise control light

M. (can't see sorry)

N. Service engine soon

O. Battery warning light

P. Airbag indicator

Q. Anti-lock brake system

R. Fuel gauge

S. Parking brake (AKA emergency brake) on

T. Low windshield washer fluid

U. Check fuel cap

V. Door ajar/open

W. Shift indicator

X. Trip odometer reset

Y. Oil pressure gauge

Z. compass/cardinal direction indicator

AA. Odometer?

You might be interested in

What are the important things to remember when arriving for an interview?

ludmilkaskok [199]

Answer: That you are dressed appropriately, to speak in a formal manner, and to be confident in your answers.

8 0

3 years ago

The penalty for littering 15 lb or less is _____.<br> A. $25<br> B. $50<br> C. $100<br> D. $150

Marina CMI [18]

Answer:

D the closest

Explanation:

i looked it up and 8t says 200

5 0

3 years ago

Three single-phase, 10 kVA, 2400/280 V, 60-Hz transformers are connected to form a three-phase, 2400/480 V transformer The equiv

Dominik [7]

The answer to this question is letter A

7 0

3 years ago

A train travels 650 meters in 25 seconds. What is the train's velocity?

frosja888 [35]

The train is traveling 26 meters A second .

3 0

3 years ago

To provide some perspective on the dimensions of atomic defects, consider a metal specimen that has a dislocation density of 105

GenaCL600 [577]

Answer:

$62.14\ \text{miles}$

$6213727.37\ \text{miles}$

Explanation:

The distance of the chain would be the product of the dislocation density and the volume of the metal.

Dislocation density = $10^5\ \text{mm}^{-2}$

Volume of the metal = $1000\ \text{mm}^3$

$10^5\times 1000=10^8\ \text{mm}\\ =10^5\ \text{m}$

$1\ \text{mile}=1609.34\ \text{m}$

$\dfrac{10^5}{1609.34}=62.14\ \text{miles}$

The chain would extend $62.14\ \text{miles}$

Dislocation density = $10^{10}\ \text{mm}^{-2}$

Volume of the metal = $1000\ \text{mm}^3$

$10^{10}\times 1000=10^{13}\ \text{mm}\\ =10^{10}\ \text{m}$

$\dfrac{10^{10}}{1609.34}=6213727.37\ \text{miles}$

The chain would extend $6213727.37\ \text{miles}$

3 0

3 years ago