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3 years ago

9

A plant that has genes for tallness may not be tall if the plant

1 answer:

Diano4ka-milaya [45]3 years ago

7 0

an allele for tallness from the tall parent and an allele for shortness from the short parent

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Given these reactions, X ( s ) + 1 2 O 2 ( g ) ⟶ XO ( s ) Δ H = − 668.5 k J / m o l XCO 3 ( s ) ⟶ XO ( s ) + CO 2 ( g ) Δ H = +

qwelly [4]

<u>Answer:</u> The $\Delta H^o_{rxn}$ for the reaction is -1052.8 kJ.

<u>Explanation:</u>

Hess’s law of constant heat summation states that the amount of heat absorbed or evolved in a given chemical equation remains the same whether the process occurs in one step or several steps.

According to this law, the chemical equation is treated as ordinary algebraic expressions and can be added or subtracted to yield the required equation. This means that the enthalpy change of the overall reaction is equal to the sum of the enthalpy changes of the intermediate reactions.

The given chemical reaction follows:

$X(s)+\frac{1}{2}O_2(g)+CO_2(g)\rightarrow XCO_3(s)$ $\Delta H^o_{rxn}=?$

The intermediate balanced chemical reaction are:

(1) $X(s)+\frac{1}{2}O_2(g)\rightarrow XO(s)$ $\Delta H_1=-668.5kJ$

(2) $XCO_3(s)\rightarrow XO(s)+CO_2$ $\Delta H_2=+384.3kJ$

The expression for enthalpy of the reaction follows:

$\Delta H^o_{rxn}=[1\times \Delta H_1]+[1\times (-\Delta H_2)]$

Putting values in above equation, we get:

$\Delta H^o_{rxn}=[(1\times (-668.5))+(1\times (-384.3))=-1052.8kJ$

Hence, the $\Delta H^o_{rxn}$ for the reaction is -1052.8 kJ.

7 0

3 years ago

Helpppp nowwww plsss!!

pogonyaev

Answer:

A

Explanation:

if the earth slows down then that will give more time to the sun meaning days/nights will be longer

5 0

2 years ago

'Suppose you take 0.0332 kg of ammonium carbonate and dissolve it using 0.0395 kg of water. What would be the mass percent conce

VMariaS [17]

The solution is 45.7 % (NH₄)₂CO₃ by mass.

Mass of solution = 0.0332 kg + 0.0395 kg = 0.0727 kg

% (NH₄)₂CO₃ = Mass of (NH₄)₂CO₃/Total mass × 100 % = 0.0332 kg/0.0727 kg × 100 % = 45.7 %

8 0

3 years ago

The specific heat of aluminum is 0.897 j/g•°c. which equation would you use to calculate the amount of heat needed to raise the

Varvara68 [4.7K]

<span>c. q = 0.75 g x 0.897 j/g•°c x 22°c</span>

7 0

3 years ago

How many cubic centimeters are there in 200 milliliters?

DiKsa [7]

Answer:

200 mL = 200 cm³

Explanation:

The relationship between cm³ and mL is 1:1.

1 cm³ = 1 mL

Thus, 200 mL is converted to cm³ as follows:

(200 mL)(1 cm³/1 mL) = 200 cm³

3 0

3 years ago