<span>strongest being phenolic acid with the highest acidity for cleaning very set in stains next it is malt vinegar good for toilets, cane vinegar good for floors and skirting board and white wine vinegar good for mixing with citric acid to clean and as already previously stated citric acid</span>
2HCl(aq) + ZnS(s) ⇒ ZnCl₂(aq) + H₂S(g)
<h3>Further explanation </h3>
Equalization of chemical reactions can be done using variables. Steps in equalizing the reaction equation:
- 1. gives a coefficient on substances involved in the equation of reaction such as a, b, or c, etc.
- 2. make an equation based on the similarity of the number of atoms where the number of atoms = coefficient × index (subscript) between reactant and product
- 3. Select the coefficient of the substance with the most complex chemical formula equal to 1
Reaction
HCl(aq) + ZnS(s) ⇒ ZnCl₂(aq) + H₂S(g)
1. give equation
aHCl(aq) + bZnS(s) ⇒ ZnCl₂(aq) + cH₂S(g)
2. make an equation
H, left=a, right=2c⇒a=2c(eq 1)
Cl, left=a, right=2⇒a=2⇒c=1(from eq 1)
Zn, left=b, right=1⇒b=1
So the equation :
2HCl(aq) + ZnS(s) ⇒ ZnCl₂(aq) + H₂S(g)
Answer:
1.784 g
Explanation:
The equation of the reaction is;
NaOH(aq) + KHC8H4O4(aq) --------> KNaC8H4O4(aq) + H2O(l)
Number of moles of NaOH reacted = 17.47/1000 * 0.5000 M
Number of moles of NaOH reacted =8.735 * 10^-3 moles
From the reaction equation;
1 mole of NaOH reacted with 1 mole of KHC8H4O4
Hence, 8.735 * 10^-3 moles of NaOH reacts with 8.735 * 10^-3 moles of KHP.
So,
Mass of KHP reacted = 8.735 * 10^-3 moles * 204.2 g/mol = 1.784 g
<h2>~<u>Solution</u> :-</h2>
- Here, to find the atomic mass of element, we must;
We know that,
- 4.6 x $ \sf{10^{22}}$ atoms of an element weigh 13.8g.
Thus,
The atoms of $ \sf{ 6.02 \times 10^{13}}$ will weigh;
- Hence, the molar mass (atomic mass) will be <u>180.6 g.</u>
3rd one:
it is very reactive because it does not have a full Valence shell.
this is because it's in group 1 so it has one electron in its outer shell, and it wants to have a full outer shell ( which it can gain by losing the electron in a reaction).
Hope this helps :)
