Answer:
Explanation:
The name tells you that this is a binary compound (contains two elements).
It contains a metal and a nonmetal, so it is a binary ionic compound. The general rule is:
Name of compound = name of metal name of ion (two words)
Name of metal = tin(IV), so the tin ion has a charge of 4+
Name of ion = bromide. Br is in Group 17, so bromide ion has charge of 1-.
Explanation:
(1) 1 m = 100 cm
1.45 m = 100 × 1.45 cm = 145 cm
(2) 1 kg = 1000 g
325 g = 0.325 kg
(3) 1 L = 1000 mL
0.0024 L= 2.4 mL
(4) 1 km = 1000 m
(5) 1 mm = 0.001 m
(6) 1 kg = 100000 cg
0.459 kg = 45900 cg
(7) 1 dm = 10⁻⁴ dm
5,995 dm = 5,995 × 10⁻⁴ km
(8) 1 g = 1000 mg
450 g = 450000 mg
(9) 1 dm = 100 m
0.003 dm = 0.3 mm
(10) 1 mL = 0.001 l
4.567 × 10⁴ mL = 45.67 L
Answer: Enthalpy of combustion (per mole) of is -2657.5 kJ
Explanation:
The chemical equation for the combustion of butane follows:
The equation for the enthalpy change of the above reaction is:
We are given:
Putting values in above equation, we get:
Enthalpy of combustion (per mole) of is -2657.5 kJ