Question

Using the quadratic formula to solve 2x2 = 4x – 7, what are the values of x? 2 plus-or-minus StartRoot 10 EndRoot i 1 plus-or-minus StartRoot 10 EndRoot i StartFraction 2 plus-or-minus StartRoot 10 EndRoot i Over 2 EndFraction 1 plus-or-minus StartRoot 5 EndRoot i

Answer 1

Answer:

C. (Check Attached image)

Step-by-step explanation:

I'm too lasy to explain but to summarize,

- add -2x^2 to both sides

- then plug the numbers into the right places

(Google quadratic formula if you don't remember)

- solve

This post was made by the quadratic Formula gang because factoring is lame.

Answer 2

Answer:

$x = 1 +/- \frac{i\sqrt{10} }{2}$

Step-by-step explanation:

The equation given is:

$2x^2 = 4x - 7\\\\2x^2 - 4x + 7 = 0$

Using quadratic formula:

$x = \frac{-b +/- \sqrt{b^2 - 4ac} }{2a}$

From the question:

a = 2, b = -4, c = 7

Therefore:

$x = \frac{4 +/- \sqrt{(-4)^2 - 4 * 2 * 7} }{2 * 2}\\\\x = \frac{4 +/- \sqrt{(16 - 56)} }{4}\\\\x = \frac{4 +/- \sqrt{-40} }{4}$

=> $x = 1 +/- \frac{i\sqrt{10} }{2}$