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s344n2d4d5 [400]
3 years ago
13

Why equation is represented by the equation on the graph

Mathematics
2 answers:
Anni [7]3 years ago
6 0

Answer:

Choice D is correct answer.

Step-by-step explanation:

We have given a line.

We have to find the equation of line.

y = mx+c is the equation of line where m denotes slope and c is y-intercept of line.

y-intercept is a point on graph where value of x is zero.

From graph,we observed that

y-intercept is 2.

c = 2

Now, select any point that is passes through the line.

(x,y) = (2,0)

Putting values in equation of line, we have

0 = m(2)+2

2m = -2

m = -1

Hence, slope is -1,

y = (-1)x+(2)

y = -x+2 is equation of line given on the graph.

Nina [5.8K]3 years ago
4 0

Answer: Option D

Step-by-step explanation:

The equation of the line, by definition, has the following form:

y=mx+b

Where m is the slope and b  is the y-intercept

As you can see in the graph, the line intercept the y-axis at 2, therefore b=2.

Now, to find the slope, choose any point of the line and solve for m:

Point (1,1)

1=m(1)+2

-1=m

Then, the equation is:

y=-x+2

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In the following pictograph, how many total books have the four groups read?
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Answer:

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Step-by-step explanation:

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3 + 2 + 2.5 + 1.5

this answer is 9

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2 years ago
Any Quetion in the steps to solve it are shown below:
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The radius of a cylinder is 3x – 2 cm. The height of the cylinder is x +3 cm. What is the
VashaNatasha [74]

Surface Area of the cylinder is 6x² + 83x - 58 cm²

Step-by-step explanation:

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7 0
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Read 2 more answers
Need help pleaseI was bad at math in school so lwant to learn
aleksklad [387]

The probability of an event is expressed as

Pr(\text{event) =}\frac{Total\text{ number of favourable/desired outcome}}{Tota\text{l number of possible outcome}}

Given:

\begin{gathered} \text{Red}\Rightarrow2 \\ \text{Green}\Rightarrow3 \\ \text{Blue}\Rightarrow2 \\ \Rightarrow Total\text{ number of balls = 2+3+2=7 balls} \end{gathered}

The probability of drwing two blue balls one after the other is expressed as

Pr(\text{blue)}\times Pr(blue)

For the first draw:

\begin{gathered} Pr(\text{blue) = }\frac{number\text{ of blue balls}}{total\text{ number of balls}} \\ =\frac{2}{7} \end{gathered}

For the second draw, we have only 1 blue ball left out of a total of 6 balls (since a blue ball with drawn earlier).

Thus,

\begin{gathered} Pr(\text{blue)}=\frac{number\text{ of blue balls left}}{total\text{ number of balls left}} \\ =\frac{1}{6} \end{gathered}

The probability of drawing two blue balls one after the other is evaluted as

\begin{gathered} \frac{1}{6}\times\frac{2}{7} \\ =\frac{1}{21} \end{gathered}

The probablity that none of the balls drawn is blue is evaluted as

\begin{gathered} 1-\frac{1}{21} \\ =\frac{20}{21} \end{gathered}

Hence, the probablity that none of the balls drawn is blue is evaluted as

\frac{20}{21}

8 0
1 year ago
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