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soldier1979 [14.2K]
3 years ago
9

A student conducted an experiment that used two rose plants to determine if a liquid formula for fertilizer was better than a dr

y formula. He tested each fertilizer on a single plant for one month, and he concluded that the liquid formula was better. When he described his conclusion to his teacher, she told him he needed to conduct additional trials. The teacher most likely asked for additional trials because A.she did not believe the new formula helped plants grow better than the old formula. B.it was necessary to see data from more plants before the conclusion could be accepted. C.it was necessary to have tested the fertilizer on different kinds of plants. D.she thought he should test additional fertilizer formulas on the same two plants.
Physics
1 answer:
Serga [27]3 years ago
4 0
B. it was necessary to see data from more plants before the conclusion could be accepted.
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Letter C on the map labels which feature of the Middle East?
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Honest, the map is so tiny, and so fuzzy when I blow it up, I really can't see anything on it clearly.  But I think maybe I do see a letter ' C ' in the eastern Mediterranean, with a curved line over to the southern Gaza strip, where it meets Sinai.  So I'll say it's the Gaza Strip.

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heat it up to above 176f or apply alternating current

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Students in a chemistry class added 5g of zinc (Zn) to 50g of hydrochloric acid (HCl). A chemical reaction occurred that produce
PilotLPTM [1.2K]

Answer:

10. 36 g ZnCl2

Explanation:

Zn + 2HCl  -> ZnCl2 + H2

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1.37 mol HCl

3 mol H2

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7 0
3 years ago
A slit has a width of W1 = 4.4 × 10-6 m. When light with a wavelength of λ1 = 487 nm passes through this slit, the width of the
Vitek1552 [10]

Answer:

The width of the central bright fringe on the screen is observed to be unchanged is 4.48*10^{-6}m

Explanation:

To solve the problem it is necessary to apply the concepts related to interference from two sources. Destructive interference produces the dark fringes.  Dark fringes in the diffraction pattern of a single slit are found at angles θ for which

w sin\theta = m\lambda

Where,

w = width

\lambda =wavelength

m is an integer, m = 1, 2, 3...

We here know that as sin\theta as w are constant, then

\frac{w_1}{\lambda_1} = \frac{w_2}{\lambda_2}

We need to find w_2, then

w_2 = \frac{w_1}{\lambda_1}\lambda_2

Replacing with our values:

w_2 = \frac{4.4*10^{-6}}{487}496

w_2 = 4.48*10^{-6}m

Therefore the width of the central bright fringe on the screen is observed to be unchanged is 4.48*10^{-6}m

3 0
3 years ago
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