Answer:
2x^2+7x-3
remainder is -4
Step-by-step explanation:
Check the image
Consider this solution, if it is possible, check the result:
1) if to divide polynomial 'x³-3x²-6x+8' on 'x+2' result is: x²-5x+4, then x³-3x²-6x+8=(x+2)(x²-5x+4);
2) x²-5x+4=(x-1)(x-4), then
3) x³-3x²-6x+8=(x+2)(x-1)(x-4).
4) zeros are: -2;1;4. Other zeros are: 1 and 4.
Answer: 1;4.
Answer:
-11x+12
Step-by-step explanation:
(x^2-4x+3)-(x^2+7x-9)
x^2-x^2-4x-7x+3-(-9)
-11x+3+9
-11x+12
Answer:The equation x² + 7 = 0 has no solution
Explanation:1- using graph:To solve the equation means graphically means to find the x-intercepts.
The attached image shows the graph of the given function.
We can note that there are no x-intercepts. This means that the given function has no real solutions
2- using algebra:To solve the equation algebraically means to find the values of x that would make the equation equal to zero.
Solving the given equation, we would find that:
x² + 7 = 0
x² = -7
x = <span>± </span>√-7
The square root of a negative number will always give imaginary values. This means that the equation has no real solutions
Hope this helps :)