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timofeeve [1]
2 years ago
11

Choose a college student at random. Decide whether each of the following is a discrete or continuous random variable:

Mathematics
1 answer:
EleoNora [17]2 years ago
5 0

Answer:

1. Discrete

2. Continuous

3. Continuous

4. Discrete

5. Continuous

6. Discrete

Step-by-step explanation:

Continuous:

Real numbers, can be integer, decimal, etc.

Discrete:

Only integer(countable values). So can be 0,1,2...

1. The number of courses the student takes this semester:

You can take 1 course, 2 courses, 3 courses, ...

Only countable values, the student cannot take 2.5 courses, for example. So discrete

2. The student's height:

Can be decimal numbers, for example, 1.8 meters. So continuous.

3. The student's (exact) body temperature:

Can be decimal numbers, for example, 96.7 ºF. Continuous.

4. The number of siblings the student has:

Cannot be decimal.

You can have 0, 1, 2, ..., 20,... siblings

Discrete

5. The (exact) time the student spends doing school work during a week:

Can be decimal, for example, 2.5 hours.

Continuous

6. The number of alcoholic beverages that the student drinks in a typical week

Zero, one, two,...

Discrete

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What fraction is 4mm of 10cm
Sever21 [200]
Answer is going to be: 4/100
8 0
2 years ago
Plz help!
Thepotemich [5.8K]

Answer:

20

Step-by-step explanation: -13 to 7 think about that. We have to add 13 to make it 0. Then we add 7. So 13 plus 7 is 20. Enjoy :)

4 0
3 years ago
I need help with this please
natka813 [3]

Answer:

Step-by-step explanation:

Antelope, Montana:  

    21, 30, 42, 58, 70, 79

Range- 58     79-21= 58

Quartile 1- 30

Quartile 3- 70

Interquartile Range- 40     70-30= 40

Augusta, Maine:

    28, 32, 41, 53, 66, 75

Range- 47

Quartile 1- 32

Quartile 3- 66

Interquartile Range- 34

3 0
3 years ago
Boris choos three diffrent numbers.the sum of the three numbers is 36.One of trh numbers is a cube number.the other two number a
inna [77]

Answer:

4,5,27

Problem:

Boris chose three different numbers.

The sum of the three numbers is 36.

One of the numbers is a perfect cube.

The other two numbers are factors of 20.

Step-by-step explanation:

Let's pretend those numbers are:

a,b, \text{ and } c.

We are given the sum is 36: a+b+c=36.

One of our numbers is a perfect cube. a=n^3 where n is an integer.

The other two numbers are factors of 20. bk=20 and ci=20 where a,c,i, \text{ and } k \text{ are integers}.

n^3+\frac{20}{k}+\frac{20}{i}=36

From here I would just try to find numbers that satisfy the conditions using trial and error.

3^3+\frac{20}{2}+\frac{20}{2}

27+10+10

47

3^3+\frac{20}{4}+\frac{20}{5}

27+5+4

36

So I have found a triple that works:

27,5,4

The numbers in ascending order is:

4,5,27

4 0
3 years ago
Please help me..asap
Ivenika [448]

Answer:

D

the first one obviously isnt random
the second one is selective then random
the third one is also selective
the fourth one is random

6 0
2 years ago
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