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3 years ago

Choose a college student at random. Decide whether each of the following is a discrete or continuous random variable:

Mathematics

1 answer:

EleoNora [17]3 years ago

5 0

Answer:

1. Discrete

2. Continuous

3. Continuous

4. Discrete

5. Continuous

6. Discrete

Step-by-step explanation:

Continuous:

Real numbers, can be integer, decimal, etc.

Discrete:

Only integer(countable values). So can be 0,1,2...

1. The number of courses the student takes this semester:

You can take 1 course, 2 courses, 3 courses, ...

Only countable values, the student cannot take 2.5 courses, for example. So discrete

2. The student's height:

Can be decimal numbers, for example, 1.8 meters. So continuous.

3. The student's (exact) body temperature:

Can be decimal numbers, for example, 96.7 ºF. Continuous.

4. The number of siblings the student has:

Cannot be decimal.

You can have 0, 1, 2, ..., 20,... siblings

Discrete

5. The (exact) time the student spends doing school work during a week:

Can be decimal, for example, 2.5 hours.

Continuous

6. The number of alcoholic beverages that the student drinks in a typical week

Zero, one, two,...

Discrete

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The probability that a male will be colorblind is .042. Find the probabilities that in a group of 53 men, the following are true

Dvinal [7]

Answer:

See below for answers and explanations

Step-by-step explanation:

Part A

$\displaystyle P(X=x)=\binom{n}{x}p^xq^{n-x}\\\\P(X=5)=\binom{53}{5}(0.042)^5(1-0.042)^{53-5}\\\\P(X=5)=\frac{53!}{(53-5)!*5!}(0.042)^5(0.958)^{48}\\\\P(X=5)\approx0.0478$

Part B

$P(X\leq5)=P(X=1)+P(X=2)+P(X=3)+P(X=4)+P(X=5)\\\\P(X\leq5)=\binom{53}{1}(0.042)^1(1-0.042)^{53-1}+\binom{53}{2}(0.042)^2(1-0.042)^{53-2}+\binom{53}{3}(0.042)^3(1-0.042)^{53-3}+\binom{53}{4}(0.042)^4(1-0.042)^{53-4}+\binom{53}{1}(0.042)^5(1-0.042)^{53-5}\\\\P(X\leq5)\approx0.9767$

Part C

$\displaystyle P(X\geq 1)=1-P(X=0)\\\\P(X\geq1)=1-(1-0.042)^{53}\\\\P(X\geq1)\approx1-0.1029\\\\P(X\geq1)\approx0.8971$

6 0

2 years ago

Jason is drawing the floor plan of his bedroom. He is drawing everything with dimensions that are 1/12 of the actual size. His b

irina [24]

Answer:

New bed dimension of bed 0.5 ft, 0.25 ft

New bed dimension of room 1.16 ft, 1.33 ft

Step-by-step explanation:

Given data:

bed dimension is given as 6 ft by 3 ft

room dimension is given as 14 ft 16 ft

according to the given information , new dimension of the room and bed will be 1/12 times of actual dimension. therefore we have

New bed dimension of bed $= \frac{1}{12} \times 6 ft, \frac{1}{12} \times 3 ft$

= 0.5 ft, 0.25 ft

New bed dimension of room $= \frac{1}{12} \times 14 ft, \frac{1}{12} \times 16 ft$

= 1.16 ft, 1.33 ft

7 0

3 years ago

What time what give me 21

Lady bird [3.3K]

21:00 would be 9:00 :)

8 0

3 years ago

Workout the value for 3x^2-5y

ale4655 [162]

Remember to do PEMDAS so your answer is not correct, since you multiplied before doing the parentheses/exponents.

Explanation:
3(3)^2- 5(4)
= 3(9) - 5(4)
= 27 - 20 = 7

6 0

2 years ago

laiz [17]

Answer:

44x +56y = 95

Step-by-step explanation:

To write the equation of the perpendicular bisector, we need to know the midpoint and we need to know the differences of the coordinates.

The midpoint is the average of the coordinate values:

((-2.5, -2) +(3, 5))/2 = (0.5, 3)/2 = (0.25, 1.5) = (h, k)

The differences of the coordinates are ...

(3, 5) -(-2.5, -2) = (3 -(-2.5), 5 -(-2)) = (5.5, 7) = (Δx, Δy)

Then the perpendicular bisector equation can be written ...

Δx(x -h) +Δy(y -k) = 0

5.5(x -0.25) +7(y -1.5) = 0

5.5x -1.375 +7y -10.5 = 0

Multiplying by 8 and subtracting the constant, we get ...

44x +56y = 95 . . . . equation of the perpendicular bisector

8 0

3 years ago