If you have to write the chemical formula of a simple, binary ionic compound given the name of the compound, you follow a set of three steps. Let's go through them using magnesium chloride as an example. Write the symbols for the cation and the anion: Mg and Cl. Determine the charge on the cation and anion.
2.45 °C
From the Ideal gas law (Combined gas law)
PV/T = P'V'/T' .....eq 1
Where:
P - initial pressure
V - initial volume
T - initial temperature
P' - final pressure
V' - final volume
T' - final temperature.
To proceed we have to make T the subject from eq.1
Which is, T = P'V'T/PV.......eq.2
We have been provided with;
Standard temperature and pressure (STP)
P = 760 mm Hg (SP - Standard Pressure)
T = 273.15 K (ST - Standard Temperature)
V = 62.65 L
P' = 612.0 mm Hg
V' = 78.31 L
T' = ? (what we require)
Therefore, we substitute the values into eq.2
T' =
.
T' = 275.60 K
T = (275.60 - 273.15) ......To °C
T = 2.45 °C
>>>>> Answer
Have a nice studies.
1) moles = mass/mR
CaCO3 Mr = 40 + 12 + (16×3)
= 52 + 48
= 100
mass = 15
so the moles would be 15 ÷ 100
which is 0.15 moles of CaCO3
2) moles = mass ÷ Mr
Mr of Al2O3 = 27 + (16×3)
= 27 + 48
= 75
mass = 204
so the moles would be 204/75 which is 2.72 moles of Al2O3
Answer:
Explanation:
Molarity = moles/liters of solution
moles = molarity x Liters of solution
= 0.350 m/L x 0.855 L
= 0.299 mol
mass = moles x molar mass
= 0.299 mol x 102.89 g/ms
= 30.78 grams
Hey there!:
Molarity HCl = 3.5 M
Volume HCl = ?
Molarity NaOH = 2.0 M
Volume NaOH in liters = 50.0 mL / 1000 => 0.05 L
Number of moles NaOH:
n = M * V
n = 2.0 * 0.05
n = 0.1 moles of NaOH
Given the reaction:
HCl + NaOH = NaCl + H2O
1 mole HCl --------- 1 mole NaOH
1 mol HCl reacts with 1 mol NaOH , so moles NaOH = moles HCl
0.1 moles of NaOH = 0.1 moles of HCl
Therefore:
M( HCl ) = n / V
3.5 = 0.1 / V
V = 0.1 / 3.5
V = 0.029 L in mL : 0.029 * 1000 => 29.0 mL
Answer B
hope that helps!
