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pentagon [3]
3 years ago
10

Based on the balanced chemical equation for the preparation of malachite, what is the composition of the bubbles formed when sod

ium carbonate is added to the solution of copper sulfate?
Chemistry
1 answer:
Flura [38]3 years ago
4 0

Answer:

Carbon Dioxide = CO2

Explanation:

The synthesis of Malachite is seen in the chemical formula:

CuSO 4 . 5H2O(aq) + 2NaCO3(aq) --> CuCO 3 Cu(OH) 2 (s) + 2Na 2 SO 4 (aq) + CO 2 (g) + 9H 2 O(l)

The bubbles mentioned in the question hints that our interest is the compounds in their gseous phase  (g).

Upon examining the chemical equation, only CO2 is in the gaseous state and hence the only one that can be formed as bubbles,

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What are the steps in naming and determining the formula of ionic compounds?
vredina [299]
If you have to write the chemical formula of a simple, binary ionic compound given the name of the compound, you follow a set of three steps. Let's go through them using magnesium chloride as an example. Write the symbols for the cation and the anion: Mg and Cl. Determine the charge on the cation and anion.
5 0
3 years ago
PLEASE HELP! WILL GIVE BRAINLIEST:
Ad libitum [116K]

2.45 °C

From the Ideal gas law (Combined gas law)

PV/T = P'V'/T' .....eq 1

Where:

P - initial pressure

V - initial volume

T - initial temperature

P' - final pressure

V' - final volume

T' - final temperature.

To proceed we have to make T the subject from eq.1

Which is, T = P'V'T/PV.......eq.2

We have been provided with;

Standard temperature and pressure (STP)

P = 760 mm Hg (SP - Standard Pressure)

T = 273.15 K (ST - Standard Temperature)

V = 62.65 L

P' = 612.0 mm Hg

V' = 78.31 L

T' = ? (what we require)

Therefore, we substitute the values into eq.2

T' =

.

T' = 275.60 K

T = (275.60 - 273.15) ......To °C

T = 2.45 °C

>>>>> Answer

Have a nice studies.

5 0
2 years ago
How many moles are there in<br> 15 grams of:<br> CaCO3<br> 204 grams of:<br> Al203
DerKrebs [107]

1) moles = mass/mR

CaCO3 Mr = 40 + 12 + (16×3)

= 52 + 48

= 100

mass = 15

so the moles would be 15 ÷ 100

which is 0.15 moles of CaCO3

2) moles = mass ÷ Mr

Mr of Al2O3 = 27 + (16×3)

= 27 + 48

= 75

mass = 204

so the moles would be 204/75 which is 2.72 moles of Al2O3

3 0
3 years ago
A student needs to make 0.855 L of a sodium bromide solution for an experiment. The concentration of the required solution is 0.
d1i1m1o1n [39]

Answer:

Explanation:

Molarity =  moles/liters of solution

moles    = molarity x Liters of solution

            =  0.350 m/L x 0.855 L

            =  0.299 mol

               mass = moles  x  molar mass    

            = 0.299 mol x 102.89 g/ms

            =  30.78 grams

4 0
3 years ago
Please help....
stiv31 [10]

Hey there!:

Molarity HCl = 3.5 M

Volume HCl = ?

Molarity NaOH = 2.0 M

Volume NaOH in liters = 50.0 mL / 1000 => 0.05 L

Number of moles NaOH:

n = M * V

n = 2.0 * 0.05

n = 0.1 moles of NaOH

Given the reaction:

HCl + NaOH = NaCl + H2O

1 mole HCl --------- 1 mole NaOH

1 mol HCl reacts with 1 mol NaOH , so moles NaOH = moles HCl

0.1 moles of NaOH = 0.1 moles of HCl

Therefore:

M( HCl ) = n / V

3.5 = 0.1 / V

V = 0.1 / 3.5

V = 0.029 L in mL :  0.029 * 1000 => 29.0 mL

Answer B

hope that helps!

5 0
3 years ago
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