Answer:
Mass = 9.58 g
Explanation:
Given data:
Mass of Zn = 2g
Theoretical yield of ZnI₂ = ?
Solution:
Chemical equation:
Zn + I₂ → ZnI₂
Number of moles of Zn:
Number of moles = mass/molar mass
Number of moles = 2g / 65.38 g/mol
Number of moles = 0.03 mol
Now we will compare the moles of Zn and ZnI₂.
Zn : ZnI₂
1 : 1
0.03 : 0.03
Mass of ZnI₂:
Mass = number of moles × molar mass
Mass = 0.03 mol × 319.22 g/mol
Mass = 9.58 g
Answer:
1188.0 mL.
Explanation:
- We can use the general law of ideal gas: PV = nRT.
where, P is the pressure of the gas in atm.
V is the volume of the gas in L.
n is the no. of moles of the gas in mol.
R is the general gas constant,
T is the temperature of the gas in K.
- If n and P are constant, and have two different values of V and T:
<em>V₁T₂ = V₂T₁
</em>
V₁ = 900 mL, T₁ = 27.0°C + 273 = 300.0 K.
V₂ = ??? mL, T₂ = 123.0°C + 273 = 396.0 K.
<em>∴ V₂ = V₁T₂/T₁ </em>= (900 mL)(396 K)/(300.0 K) = <em>1188.0 mL.</em>
Answer:
your answer would be 45 because you go up
Answer:
the volume = 9.99 ml
Explanation:
in your Q we need to calculate the volume does the pipet deliver so , we are going to use this formula:
the volume = mass / density
here we need to know the density of water at a certain temperature 19 degrees Celsius ,so I used an external source to get the density of water at 19 degrees Celsius because it is changing with different temperatures
where mass here = 9.98 g
and the density of water at temperature 19 degrees Celsius= 0.998405mL
-1
by substitution :
the volume = 9.98 g / 0.998405mL
-1
≅ 9.996 ml = 10 ml
