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3 years ago

PLEASE HELP ILL MARK BRAINLYIST

Mathematics

1 answer:

bulgar [2K]3 years ago

7 0

Answer:

The probability is $\frac{5}{22}$

Step-by-step explanation:

we know that

The probability of an event is the ratio of the size of the event space to the size of the sample space.

The size of the sample space is the total number of possible outcomes

The event space is the number of outcomes in the event you are interested in.

Let

x------> size of the event space

y-----> size of the sample space

$P=\frac{x}{y}$

In this problem we have

$x=5\ boxes\ of\ thin\ Mints$

$y=5+7+10=22\ total\ boxes$

substitute

$P=\frac{5}{22}$

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Solve 2x + 4 > 16<br> A. X < 6<br> B. X > 6<br> C. X < 10<br> D. X > 10

Korvikt [17]

Answer:

2(6)+4 > 16 x > 6 2(7) + 4 > 16

12+4=16 14+4>16 18>16

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4 years ago

I need help! (HAPPY MLK DAY!!!)

olga2289 [7]

The slope and length of the given sides of the quadrilateral can be

found by using the coordinates of the vertices.

Correct responses:

$Slope \ of \ \overline{IJ} = \underline{-\dfrac{7}{6} }$ , Length of $\overline{IJ}$ = $\underline{\sqrt{85} }$

$Slope \ of \ \overline{JK} = \underline {-\dfrac{2}{9}}$ , Length of $\overline{JK}$ = $\underline{\sqrt{85} }$

$Slope \ of \ \overline{KL} = \underline{-\dfrac{7}{6} }$ , Length of $\overline{KL}$ = $\underline{\sqrt{85}}$

$Slope \ of \ \overline{LI} = \underline{ -\dfrac{2}{9} }$ , Length of $\overline{LI}$ = $\underline{\sqrt{85} }$

<h3>Methods used to find the slope and length of a line</h3>

The given coordinates of the vertices are;

K(-7, 0), J(2, -2), I(8, -9), L(-1, -7)

$Slope = \mathbf{\dfrac{y_2 - y_1}{x_2 - x_1}}$

$Length \ of \ line = \mathbf{ \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}}$

Therefore;

$Slope \ of \ \mathbf{\overline{IJ}} = \dfrac{-2 - (-9)}{2 - 8} = \dfrac{7}{-6} = \underline{ -\dfrac{7}{6}}$

$Length \ of \ \mathbf{\overline{IJ}} = \sqrt{(2 - 8)^2 + (-2 - (-9))^2} = \underline{\sqrt{85}}$

$Slope \ of \ \mathbf{\overline{JK}} = \dfrac{0 - (-2)}{-7 - 2} = \dfrac{2}{-9} = \underline{-\dfrac{2}{9}}$

$Length \ of \ \mathbf{\overline{JK}} = \sqrt{(-7 - 2)^2 + (0 - (-2))^2} = \underline{ \sqrt{85}}$

$Slope \ of \ \mathbf{\overline{KL}} = \dfrac{0 - (-7)}{-7 - (-1)} = \dfrac{7}{-6} = \underline{ -\dfrac{7}{6}}$

$Length \ of \ \mathbf{\overline{KL} }= \sqrt{(-7 - (-1))^2 + (0 - (-7))^2} =\underline{ \sqrt{85}}$

$Slope \ of \ \mathbf{\overline{LI}} = \dfrac{(-9 - (-7))}{(8 - (-1))} = \dfrac{-2}{9} = \underline{-\dfrac{2}{9}}$

$Length \ of \ \mathbf{\overline{LI}} = \sqrt{(8 - (-1))^2 + (-9 - (-7))^2} = \underline{\sqrt{85}}$

Learn more about finding the slope and length of a line here:

brainly.com/question/11612395

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Answer:

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igor_vitrenko [27]

A

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Step-by-step explanation:

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