Answer:
The electrical force between the given charges remains the same.
Explanation:
The expression for the electrical force is as follows as;
![F=\frac{kq_{1}q_{2}}{R^{2}}](https://tex.z-dn.net/?f=F%3D%5Cfrac%7Bkq_%7B1%7Dq_%7B2%7D%7D%7BR%5E%7B2%7D%7D)
Here, k is the constant,
are the charges, F is the electrical force and R is the distance between the charges.
It is given in the problem that the magnitudes of the charges and the magnitudes of the separation between the charges are doubled.
Then, the expression of the electrical force becomes as;
![F'=\frac{k(2q_{1})(2q_{2})}{(2R)^{2}}](https://tex.z-dn.net/?f=F%27%3D%5Cfrac%7Bk%282q_%7B1%7D%29%282q_%7B2%7D%29%7D%7B%282R%29%5E%7B2%7D%7D)
![F'=\frac{k4q_{1}q_{2}}{4R^{2}}](https://tex.z-dn.net/?f=F%27%3D%5Cfrac%7Bk4q_%7B1%7Dq_%7B2%7D%7D%7B4R%5E%7B2%7D%7D)
![F'=\frac{kq_{1}q_{2}}{R^{2}}](https://tex.z-dn.net/?f=F%27%3D%5Cfrac%7Bkq_%7B1%7Dq_%7B2%7D%7D%7BR%5E%7B2%7D%7D)
![F'=F](https://tex.z-dn.net/?f=F%27%3DF)
Therefore, the electrical force between the given charges remains the same.
C Not enough information,not clear on what you are asking for
Carbon-14 is a naturally occurring carbon isotope.
Carbon-14 has a known half-life.
Carbon-14 is present in all living organisms.
Answer:
acceleration of car B appears at slowing down by 16 km/h each second
Explanation:
As we know by the concept of relative acceleration
![a_{BA} = a_B - a_A](https://tex.z-dn.net/?f=a_%7BBA%7D%20%3D%20a_B%20-%20a_A)
now we know that
Car A is moving with speed 100 km/h such that its speed is increasing at rate of 8 km/h each second
so acceleration of car A is given as
![a_A = 8 km/h/s](https://tex.z-dn.net/?f=a_A%20%3D%208%20km%2Fh%2Fs)
now car B is also moving at same speed of 100 km/h but its speed is slowing down at rate of 8 km/h each second
so acceleration of car B is negative as it is decelerating
![a_B = - 8 km/h/s](https://tex.z-dn.net/?f=a_B%20%3D%20-%208%20km%2Fh%2Fs)
So here we have from above formula
![a_{BA} = a_B - a_A = - 8 - 8 = -16 km/h/s](https://tex.z-dn.net/?f=a_%7BBA%7D%20%3D%20a_B%20-%20a_A%20%3D%20-%208%20-%208%20%3D%20-16%20km%2Fh%2Fs)
so acceleration of car B appears at slowing down by 16 km/h each second