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Sindrei [870]
3 years ago
14

Currents in dc transmission lines can be 100 A or higher. Some people are concerned that the electromagnetic fields from such li

nes near their homes could pose health dangers. For a line that has current 180 A and a height of 80 m above the ground, what magnetic field does the line produce at ground level?
Physics
1 answer:
Andrews [41]3 years ago
3 0

Answer:

B = 4.5 x 10⁻⁷ T = 0.45 μT

Explanation:

From Ampere's law the magnetic field at a certain radius from straight current-carrying wire is given by the following formula:

B = \frac{\mu_oI}{2\pi r}

where,

B = magnetic field = ?

\mu_o = permeability of free space = 4π x 10⁻⁷ H/m

I = current = 180 A

r = radius = 80 m

Therefore,

B=\frac{(4\pi\ x\ 10^{-7}\ H/m)(180\ A)}{2\pi (80\ m)}\\\\

<u>B = 4.5 x 10⁻⁷ T = 0.45 μT</u>

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