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3 years ago

6

Put these into the correct sequence: A) Ride flies into space for the first time; B) Ride serves on the Challenger accident boar

d; C) Ride becomes an author
Ride is Sally Ride

2 answers:

balu736 [363]3 years ago

8 0

Well since I don't really understand the question, I will say : B,A,C !

Nesterboy [21]3 years ago

6 0

I think it is A, B, C. :)
Good luck!

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Two identical asteroids travel side by side while touching one another. If the asteroids are composed of homogeneous pure iron a

victus00 [196]

Answer:

diameter = 21.81 ft

Explanation:

The gravitational force equation is:

$F=\frac{GMm}{R^{2} }$

Where:

F => Gravitational force or force of attraction between two masses
M => Mass of asteroid 1
m => Mass of asteroid 2
R => Distance between asteroids 1 and 2 (from center of gravity)

We also know that the asteroids are identical so their masses are identical:

M=m

Since R is the distance between centers of the two asteroids and their diameters are identical (see attachment), we can conclude that:

R=d=2r

We don´t know the mass of the asteroids but we know they are composed of pure iron, so we can relate their masses to their density:

m=ρV

This is going to be helpful because the volume of a sphere is:

$\frac{4}{3}\pi r^{3}$

And know we can write our original force of gravity equation in terms of the radius of the asteroids:

$F=\frac{GMm}{R^{2} } =\frac{Gmm}{(2r)^{2} } =\frac{Gm^{2} }{4r^{2} }$
$F=\frac{G ( \frac{4}{3}\pi r^{3}ρ)^{2} }{4r^{2} }$
$F= \frac{G(16)\pi ^{2} r^{6} ρ^{2}}{(9)(4)r^{2} } =\frac{G(16)\pi ^{2} r^{4}ρ^{2} }{36}$

Now let´s plug in the values we know:

$F = 1 lb$ mutual gravitational attraction force
$G = 6.67(10)^{-11}$ gravitational constant
$ρ_{iron} =491.5 \frac{lb}{ft^{3} }$

$1= \frac{6.67(10)^{-11} \pi ^{2} r^{4} (491.5)^{2}}{36}$

Solve for r and multiply by 2 because 2r = diameter

$d=2\sqrt[4]{\frac{1}{7.07(10)^{-5} } }$

Result is d = 21.81 Feet

6 0

2 years ago

Structures on a bird feather act like a diffraction grating having 8000 8000 lines per centimeter. What is the angle of the firs

sammy [17]

Answer:

Angle of first order maximum, $\theta=21.19^{\circ}$

Explanation:

Given that,

Wavelength of the light, $\lambda=452\ nm=452\times 10^{-9}\ m$

Number of lines, N = 8000 per cm

The relation between the number of lines and the slit width is given by :

$d=\dfrac{1}{N}$

$d=\dfrac{1}{8000/cm}$

$d=0.000125\ cm=1.25\times 10^{-6}\ m$

The equation of grating is given by :

$d\ sin\theta=n\lambda$

n = 1

$sin\theta=\dfrac{\lambda}{d}$

$sin\theta=\dfrac{452\times 10^{-9}}{1.25\times 10^{-6}}$

$\theta=21.19^{\circ}$

So, the angle of the first-order maximum is 21.19 degrees. Hence, this is the required solution.

6 0

3 years ago

At a depth of 10.9 km, the Challenger Deep in the Marianas Trench of the Pacific Ocean is the deepest site in any ocean. Yet, in

bearhunter [10]

Answer:

$P = 1.09 \times 10^8 Pa$

Explanation:

As we know that the pressure inside the liquid level is given as

$P = \rho g h + P_o$

here we have

$\rho = 1024 kg/m^3$

h = 10.9 km

also we know that

$P_o = 1.01 \times 10^5 Pa$

now we have

$P = (1.01 \times 10^5) + (1024)(9.81)(10.9 \times 10^3)$

$P = 1.09 \times 10^8 Pa$

8 0

2 years ago

A charge +Q is located at the origin and a second charge, +4Q, is at distance (d) on the x-axis.

tatiyna

Answer:

a) x = ⅔ d , b) the charge must be negative, c) Q

Explanation:

a) In this exercise the force is electric between the charges, we are asked that the system of the three charges is in equilibrium, we use Newton's second law. Balance is on the third load that we are placing

∑ F = 0

-F₁₂ + F₂₃ = 0

F₁₂ = F₂₃

let's replace the values

k Q Q / r₁₂² = k Q 4Q / r₂₃²

Q² / r₁₂² = 4 Q² / r₂₃²

suppose charge 3 is placed at point x

r₁₂ = x

r₂₃ = d-x

we substitute

1 / x² = 4 / (d-x) 2

1 / x = 2 / (d-x)

x = 2 (x-d)

x = 2x -2d

3x = 2d

x = ⅔ d

b) The sign of the charge must be negative, to have an attractive charge on the two initial charges

c) Q

5 0

3 years ago

You use 350 W of power to move a 7.0 N object 5 m.<br> How long did it take?

PilotLPTM [1.2K]

Answer:

0.1 second

Explanation:

We are given;

Power; P = 350 W

Force; F = 7 N

Distance; d = 5 m

Formula for power is;

P = workdone/time taken

Workdone = F × d

Thus;

350 = (7 × 5)/t

t = 35/350

t = 0.1 second

4 0

3 years ago