Answer:
1/6 m/s^2 ( about 1/6th gravity of Earth ( 9.81 m/s^2)
Explanation:
Displacement = yo + vo t - 1/2 a t^2
- 3.2 = 0 + 0 - 1/2 a(2.0)^2
- 3.2 = -2a
a = 3.2 / 2 = 1.6 m/s^2
Answer:
The ratio of their distance is 9:1
Solution:
As per the question:
Suppose,
Mass of the lighter block = m
Mass of the heavier block, M = 3m
Velocity of the lighter block be v and the velocity of the heavier block be v'.
Now,
The initial momentum of the system is zero.
Therefore,
mv + Mv' = 0
mv = - Mv'
mv = - 3mv'
(1)
Now, if the distance covered by the lighter and the heavier block be d and d' respectively, then by the kinematic eqn:
(2)
(3)
Dividing eqn (2) by (3), we get:
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She could melt 75g of lead at 1637.5 C