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Shtirlitz [24]
3 years ago
10

A small boat is moving at a velocity of 3.35m/s when it is accelerated by a river current perpendicular to the initial direction

of motion. The current accelerates the boat at 0.750m/s^2. what will the new velocity (magnitude and direction) of the boat be after 5 s?
Physics
1 answer:
mr_godi [17]3 years ago
7 0

Answer:

 v =7.1 m/s

Explanation:

Given that

u = 3.35 m/s

t= 5 s

a= 0.75 m/s²

The final velocity = v

We know v = u +at

v=final velocity

u=initial velocity

Now by putting the values in the above equation

v = 3.35 + 0.75 x 5 m/s

v =7.1 m/s

Therefore the final velocity will be 7.1 m/s

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A spring has a natural length of 0.5 m and was stretched by 0.02 m. if the spring had a resultant energy of 0.5 j what is the sp
Anna71 [15]

\textbf{2500 }\dfrac{\textbf{kg}}{\textbf{s}^{\textbf{2}}}

Explanation:

       Natural length of a spring is 0.5\text{ }m. The spring is streched by 0.02\text{ }m. The resultant energy of the spring is 0.5\text{ }J.

       The potential energy of an ideal spring with spring constant k and elongation x is given by \dfrac{1}{2}kx^{2}.

       So, in the current problem, the natural length of the spring is not required to find the spring constant k.

       \text{Potential Energy in the spring = }\dfrac{1}{2}kx^{2}\\0.5\text{ }J\text{ }=\text{ }\dfrac{1}{2}k(0.02\text{ }m)^{2}\\k\times0.0004\text{ }m^{2}\text{ }=\text{ }1\text{ }J\text{ }=\text{ }1\text{ }kg\frac{m^{2}}{s^{2}}\\k\text{ }=\text{ }\dfrac{1\text{ }kg\dfrac{m^{2}}{s^{2}}}{0.0004\text{ }m^{2}}\text{ }=\text{ }2500\text{ }\frac{kg}{s^{2}}

∴ The spring constant of the spring = 2500\text{ }\frac{kg}{s^{2}}

4 0
4 years ago
Why are the valence electrons of carbon important?
Tatiana [17]
Carbon is an important compound on the earth. This is really visible in Carbon Dioxide. The valence electrons are important because they allow many different types of bonds to occur. 
7 0
3 years ago
Light travels 186,282 miles in one second. A light year is the distance light travels in one year. It is about 4.3 light years t
deff fn [24]

Answer:

2.5278035226\times 10^{13}\ miles

1994.7944465 miles

46390568.5227 miles

125 ft

Explanation:

1\ ly=186282\times 365.25\times 24\times 60\times 60=5.8786128432\times 10^{12}\ mi

4.3\ ly=4.3\times 5.8786128432\times 10^{12}=2.5278035226\times 10^{13}\ miles

The distance is 2.5278035226\times 10^{13}\ miles

2000\ miles=0.01\ in

2.5278035226\times 10^{13}\times \dfrac{1}{2000}=1.2639017613\times 10^{10}\ LA\ to\ NY

Converting to inches

1.2639017613\times 10^{10}\times 0.01=126390176.13\ in/LA\ to\ NY

Converting to miles

126390176.13\times\dfrac{1}{5280\times 12}=1994.7944465\ inches/LA\ to\ NY

The distance is 1994.7944465 miles

5.8786128432\times 10^{17}\times \dfrac{1}{2000}\times 0.01\times\dfrac{1}{5280\times 12}=46390568.5227\ miles

The distance is 46390568.5227 miles

5.8786128432\times 10^{12}\times 15\times 10^{9}=8.8179192648\times 10^{22}

8.8179192648\times 10^{22}\times \dfrac{1}{5.8786128432\times 10^{17}}=150000\ MW\ dia

150000\dfrac{1}{100\times 12}=125\ ft

The distance is 125 ft

5 0
4 years ago
The area of the effort and load of the Piston of a hydrolic are 0.5 and 5m respectively. If a force of 100 Newton is applied on
Yanka [14]

Answer:

Explanation:

Using Pascal laws, which states that pressure are the input equals the pressure at the output.

Pressure is given as force/area

P1=P2

Then,

F1/A1=F2/A2

Cross multiply

F1A2=F2A1

Given that

Ae=0.5m² area of effort

Al=5m² area of load

Fl=? Force if load

Fe= 100N. Force of effort

Then applying pascal

Fl/Al=Fe/Ae

Fl/5=100/0.5

FL/5=200

Fl=200×5

Fl=1000N

The first safety load is 1000N

6 0
4 years ago
The current through a 10 ohm resistor is 1.2 amperes.What is the potential difference across the resistor?
Natalija [7]

<u>Answer</u>: The potential difference across the resistor is 12 volts.

<u>Explanation:</u>

To calculate the potential difference cross the resistor, we use Ohm's Law. This law states that the potential difference across two wires is directly proportional to the current flowing through that wire.

Mathematically,

V\propto I\\V=IR

Where,

V = potential difference = ?V

I = Current flowing = 1.2 A

R = Resistor = 10\Omega

Putting values in above equation, we get:

V=1.2\times 10=12V

Hence, the potential difference across the resistor is 12 volts

6 0
3 years ago
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