A small boat is moving at a velocity of 3.35m/s when it is accelerated by a river current perpendicular to the initial direction
1 answer:
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Answer:
(a) I_A=1/12ML²
(b) I_B=1/3ML²
Explanation:
We know that the moment of inertia of a rod of mass M and lenght L about its center is 1/12ML².
(a) If the rod is bent exactly at its center, the distance from every point of the rod to the axis doesn't change. Since the moment of inertia depends on the distance of every mass to this axis, the moment of inertia remains the same. In other words, I_A=1/12ML².
(b) The two ends and the point where the two segments meet form an isorrectangle triangle. So the distance between the ends d can be calculated using the Pythagorean Theorem:
Next, the point where the two segments meet, the midpoint of the line connecting the two ends of the rod, and an end of the rod form another rectangle triangle, so we can calculate the distance between the two axis x using Pythagorean Theorem again:
Finally, using the Parallel Axis Theorem, we calculate I_B:
The resistance of the cylindrical wire is .
Here is the resistance,
is the length of the wire and
is the area of
cross section. Since the wire is cylindrical
.
Comparing two wires,
Dividing the above 2 equations,
Since
The above ratio is
We also have,
The current through the Silver wire will be 4.23 times the current through the original wire.
This is a diagram from above, the air resistance is oppose to movement, the bird is moving forward given its force is bigger.
