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Shtirlitz [24]
3 years ago
10

A small boat is moving at a velocity of 3.35m/s when it is accelerated by a river current perpendicular to the initial direction

of motion. The current accelerates the boat at 0.750m/s^2. what will the new velocity (magnitude and direction) of the boat be after 5 s?
Physics
1 answer:
mr_godi [17]3 years ago
7 0

Answer:

 v =7.1 m/s

Explanation:

Given that

u = 3.35 m/s

t= 5 s

a= 0.75 m/s²

The final velocity = v

We know v = u +at

v=final velocity

u=initial velocity

Now by putting the values in the above equation

v = 3.35 + 0.75 x 5 m/s

v =7.1 m/s

Therefore the final velocity will be 7.1 m/s

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A lamp is marked 24V, 100W. Describe an experiment to check that the electrical power supplied to the lamp is 100W when the p.d.
topjm [15]

The electrical power supplied to the lamp is 100W when the p.d. across it is 24V and the current is 4.2 A.

<h3>What is electrical power?</h3>

Electrical power is the rate at which electrical work is done.

The unit of electrical power is Watts.

  • Power = Current × Voltage

The experiment will require a 24V Battery, a Lamp marked 24V, 100 W, a key, wires, a rheostat, a voltmeter and an ammeter.

The circuit is completed and the rheostat is adjusted to provide until the voltmeter reads 24V.

The ammeter reading is taken as well.

When the voltmeter reading is 24V, it can be seen that' the ammeter reading for current is approximately 4.2 A.

Calculating, the power of the lamp:

Power = 24 × 4.2 = 100 W

Therefore, the electrical power supplied to the lamp is 100W when the p.d. across it is 24V and the current is 4.2 A.

Learn more about power and p.d. at: https://brainly.in/question/13629965

3 0
2 years ago
A square loop of wire, with sides of length a, lies in the first quadrant of the xy plane, with one corner at the origin. In thi
Ainat [17]

Answer:

emf=-\dfrac{1}{2}kta^5

Explanation:

Given that

B(y, t) = k y ³t²

To find the total flux over the loop we have to integrate over the loop

\phi =\int B.dS

Given that loop is square,so

\phi =\int B.dS

B(y, t) = k y ³t²

\phi =kt^2\int_{0}^{a}dx\int_{0}^{a}y^3dy

\phi =\dfrac{1}{4}kt^2a^5

We know that emf given as

emf=-\dfrac{d\phi }{dt}

\phi =\dfrac{1}{4}kt^2a^5

So

emf=-\dfrac{1}{2}kta^5

5 0
3 years ago
A child standing on a bus remains still when the bus is at rest. when the bus moves forward and then slows down, the child conti
kati45 [8]
I'm pretty sure the answer to this question is "newton's first law of motion" or d. Hope this helps. :)

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A football is kicked 18m/s at 20 degrees. what is the acceleration rate in the horizontal direction
fomenos

If we ignore air resistance, as we always do,
there is no horizontal acceleration.

Gravity acts only in the vertical direction, and
no other forces act on the ball after the punt.

6 0
3 years ago
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