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ella [17]
3 years ago
9

You want to estimate the mean amount of time college students spend on the Internet each month. How many college students must y

ou survey to be 95% confident that your sample mean
Mathematics
1 answer:
KonstantinChe [14]3 years ago
8 0

Answer:

752.95

Step-by-step explanation:

Data provided in the question

The standard deviation of population = 210

The Margin of error = 15

The confidence level is 75%, so the z value is 1.96

Now the required sample size is

= 1.96^2\times \frac{210^2}{15^2}

= 752.95

Hence, the number of college students spends on the internet each month is 752.95

Simply we considered the above values so that the n could come

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Find the difference of 5 7/8 - 1/4
otez555 [7]

Answer:

5 5/8

Step-by-step explanation:

i hope this helped have a good one

3 0
3 years ago
65% of what number is 39?
aleksklad [387]
You have to turn 65 into a decimal. That would be .65
They do 39/.65
You should get 60 as your final answer.
6 0
3 years ago
Read 2 more answers
Jim and Jackie are married with three children at home and a mortgage. Jim’s net pay per year is $67,000 and Jackie does not hav
rodikova [14]

The correct option is that they should work on their plan for managing income.

<h3>How to illustrate the information?</h3>

Given that Jim and Jackie are married with three children and have a home at mortgage.

The net pay per year of Jim is $67,000 and Jackie do not earn at all. The mortgage expenses and monthly expenses are

$(2,800+2,700) = $5,500, not much as compared to the total income.

Also, Jim contributes 15% of his income , i.e., $10050 into the retirement fund and also they have savings of $5,000.

In addition, there is a $500,000 life insurance policy on Jim and a $100,000 policy on Jackie.

Therefore, looking at all of these, it can be concluded that the net income of Jim per year is not bad at all to manage the expenses, they just have to work on it little more to run the family smoothly.

Thus, the correct option is that they should work on their plan for managing income.

Learn more about income on:

brainly.com/question/25745683

#SPJ1

Complete question:

Jim and Jackie are married with three children at home and a mortgage. Jim’s net pay per year is $67,000 and Jackie does not have income. Their mortgage payment of $2,800 includes insurance on their home. They have additional monthly expenses of $2,700. Jim contributes 15% of his earnings to a retirement fund and they have $5,000 in savings. There is a $500,000 life insurance policy on Jim and a $100,000 policy on Jackie. As their financial advisor, what part of Jim and Jackie’s financial plan would you encourage them to work on? a. They should work on their plan for managing income. b. They should work on their plan for managing their liquidity. c. They should work on their plan for protecting their assets. d. They should work on their plan for protecting their income.

3 0
1 year ago
A family is driving from Phoenix to San Francisco. On a map grid, Phoenix is located at (–12, –16), and San Francisco is located
makkiz [27]
The answer is 34.05

The total distance (D) is the sum of three distances (d1, d2, and d3).

The distance formula is d = \sqrt{(x2-x1)^{2} +(y2-y1)^{2}}

Distance 1: Phoenix (–12, –16) to Blythe (–20, –9)<span>:
</span>d1 = \sqrt{(-20-(-12))^{2} +(-9-(-16))^{2}} =\sqrt{(-20+12)^{2} +(-9+16)^{2}} \\ =\sqrt{(-8)^{2} +(7)^{2}}= \sqrt{64+49} = \sqrt{113}= 10.63

Distance 2: Blythe (–20, –9) to Los Angeles (–33, –4):
d2 = \sqrt{(-33-(-20))^{2} +(-4-(-9))^{2}} =\sqrt{(-33+20)^{2} +(-4+9)^{2}} \\ =\sqrt{(-13)^{2} +(5)^{2}}= \sqrt{169+25} = \sqrt{194}= 13.93

Distance 3: Los Angeles (–33, –4) to <span>San Francisco (–36, 5)
</span>d3 = \sqrt{(-36-(-33))^{2} +(5-(-4))^{2}} =\sqrt{(-36+33)^{2} +(5+4)^{2}} \\ =\sqrt{(-3)^{2} +(9)^{2}}= \sqrt{9+81} = \sqrt{90}= 9.49
<span>
D = d1 + d2 + d3 = 10.63 + 13.93 + 9.49 = 34.05</span>
3 0
3 years ago
the excursion boat on the river takes 2 1/2 hours to make the trip to a point 12 miles up stream and to return. If the rate at w
MissTica
Let V, be the rate in still water and let C = rate river current
If the boat is going :
upstream, its rate is V-C and if going 
downstream, its rate is V+C,
But V = 5C, then
Upstream Rate: 5C - C = 4 C
Downstream rate: 5C+C = 6C

Time = distance/Rate,  (or time = distance/speed) , then:
Upstream time 12/4C and
Downstream time: 12/.6C

Upstream time +downstream time:= 2h30 ' then:

12/4C + 12/.6C = 2.5 hours
3/C + 2/C = 5/2 (2.5 h = 5/2)
Reduce to same denominator :
 5C = 10 and Rate of the current = 2 mi/h

4 0
3 years ago
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