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ella [17]
3 years ago
9

You want to estimate the mean amount of time college students spend on the Internet each month. How many college students must y

ou survey to be 95% confident that your sample mean
Mathematics
1 answer:
KonstantinChe [14]3 years ago
8 0

Answer:

752.95

Step-by-step explanation:

Data provided in the question

The standard deviation of population = 210

The Margin of error = 15

The confidence level is 75%, so the z value is 1.96

Now the required sample size is

= 1.96^2\times \frac{210^2}{15^2}

= 752.95

Hence, the number of college students spends on the internet each month is 752.95

Simply we considered the above values so that the n could come

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write the slope - intercept equation of the line that passes through the point (6, "-1)" and has a slope of "-1/3"
andreev551 [17]

Answer:

-1 = 1/3 * 6 - 3

Step-by-step explanation:

So if it goes through point (6, -1) and has a slope of -1/3, all of this is parts of the slope intercept equal, Y = mx - B. You have the slope, which is m in the equation, y = -1/3 x - b. you already have a y and x which are the points passed, -1 = -1/3 * 6 - b, but this can't equal y, so you must have did it wrong, the only way this could equal y is if the slope wasn't negative, and in that case it would be -1 = 1/3 * 6 - 3. Because 1/3 * 6 is 2 and then subract 3 and you get -1.

5 0
2 years ago
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MEDALS REWARDED!. . Find the exact value of (cos-1) square root of two divided by two.
HACTEHA [7]

The exact value of the given equation is 45 degrees or pi/4. I am hoping that this answer has satisfied your query about and it will be able to help you, and if you’d like, feel free to ask another question.

4 0
3 years ago
If a rectangle has an area of x^2+x-20 and a width of x-4, what is the length?
Mrac [35]

Answer:

This (x - 5) represents the length of the rectangle.

Step-by-step explanation:

The formula for the area of a rectangle of length L and width W is A = L * W.

Here, the width is x - 4 and the area is x^2 + x - 20.  Dividing the width (x - 4) into the area results in an expression for the length:

x - 4  /   x^2 + x - 20

Let's use synthetic division here.  It's a little faster than long division.

If the divisor in long division is x - 4, we know immediately that the divisor in synthetic division is 4:

4   /   1    1    -20

              4     20

    --------------------

         1     5     0

This synthetic division results in a remainder of 0.  This tells us that 4 (or the corresponding (x - 4) is indeed a root of the polynomial x^2 + x - 20, and so *(x - 4) is a factor.  From the coefficients 1 and 5 we can construct the other factor:  (x - 5).  This (x - 5) represents the length of the rectangle.

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2 years ago
What is the least common multiple of 15 and 6?<br><br> Take notes and show your work.
Mariulka [41]
Hello!

The least common multiple is 3

Hope this helps!
4 0
3 years ago
The length of the base edge of a pyramid with a regular hexagon base is represented as x. The height of the pyramid is 3 times l
sergij07 [2.7K]

Answer:

(a)

h=3x

(b)

A=\frac{\sqrt{3} }{4} x^2

(c)

A=\frac{3\sqrt{3} }{2} x^2

(d)

V=\frac{3\sqrt{3} }{2} x^3 units^3

Step-by-step explanation:

We are given a regular hexagon pyramid

Since, it is regular hexagon

so, value of edge of all sides must be same

The length of the base edge of a pyramid with a regular hexagon base is represented as x

so, edge of base =x

b=x

Let's assume each blank spaces as a , b , c, d

we will find value for each spaces

(a)

The height of the pyramid is 3 times longer than the base edge

so, height =3*edge of base

height=3x

h=3x

(b)

Since, it is in units^2

so, it is given to find area

we know that

area of equilateral triangle is

=\frac{\sqrt{3} }{4} b^2

h=3x

b=x

now, we can plug values

A=\frac{\sqrt{3} }{4} x^2

(c)

we know that

there are six such triangles in the base of hexagon

So,

Area of base of hexagon = 6* (area of triangle)

Area of base of hexagon is

=6\times \frac{\sqrt{3} }{4} x^2

=\frac{3\sqrt{3} }{2} x^2

(d)

Volume=(1/3)* (Area of hexagon)*(height of pyramid)

now, we can plug values

Volume is

=\frac{1}{3}\times\frac{3\sqrt{3} }{2} x^2\times (3x)

V=\frac{3\sqrt{3} }{2} x^3 units^3


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3 years ago
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