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Nonamiya [84]
4 years ago
5

HELP.!!!!

Mathematics
1 answer:
k0ka [10]4 years ago
5 0

Answer:

A . (2x + 9) and (x-4)

Explanation:

Given parameters:

 Given trinomial;

               2x² + x - 36

Possible dimensions of the yard = ?

Solution:

To solve this apply the quadratic factorization;

        2x² + x - 36 = 0

        2x² -8x  + 9x - 36  = 0

        2x(x - 4) + 9(x -4) = 0

      (2x + 9) (x -4) = 0

The possible dimensions of the rectangular yard is (2x + 9)  and (x -4)

 

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What is the length of the hypotenuse?
Charra [1.4K]

Answer:

Hello! answer: 85

Step-by-step explanation:

68 × 68 = 4624

51 × 51 = 2601

4624 + 2601 = 7225

√7225 = 85

85 × 85 = 7225 therefore c = 85 Hope that helps!

7 0
3 years ago
Read 2 more answers
Help I need help in number 1 and 2 plz asap
bonufazy [111]
1. 
C= 3.14 * 9
C= 28.26
The circumference is 28.3 cm......

2.
C=3.14 * (2*13)
C=3.14 * 26
C= 29.14
The circumference is 19.1 cm....



7 0
3 years ago
3(4x+2) - 6x = 5x - 5(2 + x)
iVinArrow [24]
3(4x+2) - 6x = 5x - 5(2 + x)
3·4x+3·2-6x=5x-5·2-5·x
12x+6-6x=5x-10-5x
12x-6x-5x+5x= -10-6
6x=-16
x=- \frac{16}{6}  \\ x=- \frac{8}{3}  \\ x=-2 \frac{2}{3}

7 0
3 years ago
Read 2 more answers
Find the closest point to y in the subspace W spanned by v1 and v
enot [183]

Answer:

The answer is

\bold{  \left[\begin{array}{c}\frac{127}{27} \\ \ &\frac{65}{18} \\ \ &\frac{76}{27}\\ \ &\frac{97}{54}\\\ \end{array}\right]}

Step-by-step explanation:

Given value:

v_1=\left[\begin{array}{c}5&4&3&2\\ \end{array}\right] \\

v_2=\left[\begin{array}{c}-4&5&-2&3\\ \end{array}\right] \\    

The value of v_1  \cdot v_2:

= \left[\begin{array}{c}5&4&3&2\\ \end{array}\right]  \left[\begin{array}{c}-4&5&-2&3\\ \end{array}\right]

The above value "v_1, v_2" are orthogonal vectors that is: v_1 \neq 0, \ \  v_2 \neq 0

\{v_1,v_2\} from the above orthogonal basis of subspace w and the shortest distanc value of vector y:

=\left[\begin{array}{c}3&9&-5&8\\\ \end{array}\right] \\\\

The value of y on W= \frac{y \cdot v_1}{v_1 \cdot v_1} \times v1 + \frac{y \cdot v_2}{v_2 \cdot v_2} \times v_2

= \frac{\left[\begin{array}{c}3&9&-5&8\\\ \end{array}\right] \cdot \left[\begin{array}{c}5&4&3&2\\ \end{array}\right] }{\left[\begin{array}{c}5&4&3&2\\ \end{array}\right] \cdot \left[\begin{array}{c}5&4&3&2\\ \end{array}\right]} \times  \left[\begin{array}{c}5&4&3&2\\ \end{array}\right]  + \frac{\left[\begin{array}{c}3&9&5&-8\\\ \end{array}\right] \cdot \left[\begin{array}{c}-4&5&-2&3\\ \end{array}\right] }{\left[\begin{array}{c}-4&5&-2&3\\ \end{array}\right] \cdot \left[\begin{array}{c}-4&5&-2&3\\ \end{array}\right]} \times  \left[\begin{array}{c}-4&5&-2&3\\ \end{array}\right]

= \frac{50}{54} \left[\begin{array}{c}5&4&3&2\\\ \end{array}\right]  - \frac{1}{54}  \left[\begin{array}{c}-4&5&-2&3\\\ \end{array}\right]\\\\

=  \left[\begin{array}{c}\frac{127}{27} \\ \ &\frac{65}{18} \\ \ &\frac{76}{27}\\ \ &\frac{97}{54}\\\ \end{array}\right]

5 0
4 years ago
Someone please help me?
MariettaO [177]
(AE + ED) *AE = (CB+ AB) *AB

(4 + ED) * 4 = (4+5) *5

(4 + ED) * 4 = 45

4ED +16 = 45

4ED = 29
ED = 29/4 = 7.25

AD = AE + ED

AD = 4 + 7.25

AD = 11.25

Answer is A
4 0
3 years ago
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