Choose the products that complete the reaction. The chemical equation may not be balanced.
2 answers:
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Answer:
Option D.
Explanation:
- 6H₂ + P₄ → 4PH₃
First we convert the given reactant masses into moles, using their respective molar masses:
- 4.00 g H₂ ÷ 2 g/mol = 2 mol H₂
- 6.20 g P₄ ÷ 124 g/mol = 0.05 mol P₄
0.05 moles of P₄ would react completely with (6*0.05) 0.3 moles of H₂. There are more H₂ moles than required, meaning H₂ is in excess and P₄ is the limiting reactant.
Now we<u> calculate how many PH₃ moles could be formed</u>, using the <em>number of moles of the limiting reactant</em>:
- 0.05 mol P₄ *
= 0.2 mol PH₃
Finally we <u>convert 0.2 mol PH₃ into grams</u>, using its <em>molar mass</em>:
- 0.2 mol PH₃ * 34 g/mol = 6.8 g
So the correct answer is option D.
<u>Answer:</u> The mass of lead iodide produced is 9.22 grams
<u>Explanation:</u>
To calculate the molarity of solution, we use the equation:
Molarity of NaI = 0.200 M
Volume of solution = 0.200 L
Putting values in above equation, we get:
The chemical equation for the reaction of NaI and lead chlorate follows:
By Stoichiometry of the reaction:
2 moles of NaI reacts produces 1 mole of lead iodide
So, 0.04 moles of NaI will react with = of lead iodide
To calculate the number of moles, we use the equation:
Molar mass of lead iodide = 461 g/mol
Moles of lead iodide= 0.02 moles
Putting values in above equation, we get:
Hence, the mass of lead iodide produced is 9.22 grams