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disa [49]
3 years ago
8

You are given two beakers A and B and China rose as an indicator .Beaker A has 20ml of magnesium hydroxIde and 100ml of water. a

nd beaker B has 50ml of magnesium hydroxide and 100ml of water. When these solutions are tested with China rose,
a. The darkness of the green color produced by the indicator were not same in each of the

solutions. What could be the possible reasons?
Chemistry
1 answer:
kicyunya [14]3 years ago
6 0

Answer:

The darkness of the green color produced in the beakers is different because the concentration of magnesium hydroxide is different in both beakers.

Explanation:

The reason why the flasks have different color intensity is related to the concentration of magnesium hydroxide.

An indicator usually changes color because its conformation changes according to the pH. The higher the base level, the pH is higher. Then the color shift will be more intense.

Beaker A has 20 ml of magnesium hydroxide and 100 ml of water and beaker B has 50ml of magnesium hydroxide and 100ml of water.

Beaker A is more diluted than beaker B.

Therefore, beaker B is greener than beaker A.

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_____ stars can be between one thousand times dimmer and one million times brighter than the Sun.
dmitriy555 [2]

Answer:

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D. Main sequence

Explanation:

Main sequence stars can be between one thousand times dimmer and one million times brighter than the Sun.

What is main sequence stars?

A main sequence star is any star that is fusing hydrogen in its core and has a stable balance of outward pressure from core nuclear fusion and gravitational forces pushing inward.

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3 years ago
Use the graph to answer these questions. For numerical answers, use correct significant digits.
kykrilka [37]

Answer:

  • 1. Letter <u>    A      </u>shows the overall enthalpy of reaction

  • 2. which is equal to kJ  <u>   2,538.90kJ   </u>

  • 3. Letter <u>    B     </u>shows the activation energy for the reaction

  • 4. The activated complex is represented by <u>   letter C   </u>

Explanation:

<em></em>

<em>1. Letter __ shows the overall enthalpy of reaction</em>

The overall enthalpy of reaction is equal to the change of enthalpy of the substances:

Enthalpy of reaction = ∑ enthalpy of the products - ∑enthalply of the reactants.

The products are shown of the right side of the diagram. They are C₆H₁₂O₆(g) and 6O₂(g).

The reactants are shown of the left side of the diagram. They are 6CO₂(g) and 6H₂O(g).

The arrow labeled A shows the difference between the enthalpies of the products and the reactants; thus this shows the overall enthalpy of reaction.

<em></em>

<em>2. which is equal to kJ__</em>

You must subtract the enthalpy of the iniital state (reactants) from the enthalpy of the final state (products).

  • Overall enthalpy of reaction = - 1,273.02kJ - ( - 3,811.92kJ)
  • Overall enthalpy of reaction = 2,538.90kJ

This is a positive change indicating the reaction is endothermic.

<em>3. Letter___shows the activation energy for the reaction</em>

The activation energy is the energy that the reactants must gain for the reaction occurs.

Thus, it is the difference between the maximum energy, indicated by the label C on the graph, and initial state.

That is shown by the arrow labeled B: the reactants must gain the amount of energy indicated by the arrow labeled B to reach the energy of the state labeled C.

<em>4. The activated complex is represented by ____</em>

<em />

The activated complex is the intermediate compound formed while the reactants are breaking their bonds and new bonds start to form the products. It is also called transition state.

The activated complex is on the top of the energy diagram because it hat the highest energy. The formation of the activated complex always requires energy (it is an endothermic process). Once it is formed, energy is released and the reactants are formed (this part is exothermic).

Thus, the activated complex is labeled with the letter C.

8 0
4 years ago
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F 2.50 × 10−2 g of solid Fe(NO3)3 is added to 100. ML of a 1.0 × 10−4 M NaOH solution, will a precipitate form? (ksp=4 × 10−38 f
vladimir1956 [14]

Answer:

A precipitate will be formed

Explanation:

The Ksp equilibrium of Fe(OH)₃ is:

Fe(OH)₃ (s) ⇄ Fe³⁺(aq)+ 3OH⁻(aq)

And its expression is:

Ksp = 4x10⁻³⁸ = [Fe³⁺] [OH⁻]³

<em>Where the concentrations are concentrations in molarity in equilibrium,</em>

We can write Q as:

Q = [Fe³⁺] [OH⁻]³

<em>Where [] are actual concentrations in molarity of each specie.</em>

<em />

When Q>= Ksp; a precipitate is formed,

When Q< Ksp no precipitate is produced:

[OH⁻] = [NaOH] = 1.0x10⁻⁴M

[Fe²⁺] = 2.50x10⁻²g * (1mol / 179.85g) / 0.100L = 1.39x10⁻³M

<em>179.85g/mol is molar mass of Fe(NO₃)₂ and the volume of the solution is 0.100L = 100mL</em>

<em />

Q = [Fe³⁺] [OH⁻]³

Q = [ 1.39x10⁻³] [ 1.0x10⁻⁴]³

Q = 3.8x10⁻¹⁵

As Q >> Ksp; A precipitate will be formed

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