Answer:
Plutonium is the second transuranium element of the actinide series.
Answer:
H-O-H polar
O-C-O nonpolar
H-C-N polar
Explanation:
Looking up the electronegativities of the atoms involved in this question, we have:
Atom Electronegativity
H 2.2
C 2.55
N 3.04
O 3.44
All of the atoms differ in electronegativity resulting in individual dipole moments in H-O, O-C, H-C and C-N bonds. To find if the molecules will be polar we need to consider the structure of the compound to see if there is a resultant dipole moment.
In H-O-H, we have 2 lone pairs of electrons around the central oxygen atom which push the angle H-O-H of the ideal tetrahedral structure to be smaller than 109.5 º resulting in an overall dipole moment making it polar.
In O-C-O, we have two dipole moments that exactly cancel each other in the linear molecule since the central carbon atom does not have lone pairs of electrons since it has 2 double bonds. Therefore the molecule is nonpolar.
In H-C-N, again we have have a central carbon atom without lone pairs of electrons and the shape of the molecule is linear. But, now we have that the dipole moment in C-N is stronger than the H-C dipole because of the difference in electronegativity of nitrogen compared to hydrogen. The molecule has an overall dipole moment and it is polar.
Using the relationship M1V1 = M2V2 where M1 and M2 are the molar concentrations (mol/L or mmol/ml) and V1 and V2 are the volumes of the solutions, we can arrive at the following answer for the given problem:
<span>15.0M (L of stock solution) = 2.35M (0.25L) *all volumes were converted to liters.
L of stock solution = (2.35*0.25)/15.0
Therefore, 0.0392L or 39.17 ml of stock solution is needed. </span>
Answer:
V = 34.3 L
Explanation:
Given data:
Volume of hydrogen produced = ?
Mass of magnesium = 36.7 g
Temperature and pressure = standard
Solution:
Mg + 2HCl → MgCl₂ + H₂
Number of moles of magnesium:
Number of moles = mass/molar mass
Number of moles = 36.7 g/ 24 g/mol
Number of moles = 1.53 mol
Now we will compare the moles of magnesium with hydrogen.
Mg : H₂
1 : 1
1.53 : 1.53
Number of moles of hydrogen produced = 1.53 mol
Volume of hydrogen:
PV = nRT
V = nRT / P
V = 1.53 mol × 0.0821 atm.L/mol.K × 273 K/ 1 atm
V = 34.3 L