Answer:
-323.4375
Step-by-step explanation:
Using the greatest common factor, it is found that the greatest dimensions each tile can have is of 3 feet.
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- The widths of the walls are of <u>27 feet, 18 feet and 30 feet.</u>
- <u>The tiles must fit the width of each wall</u>, thus, the greatest dimension they can have is the greatest common factor of 27, 18 and 30.
To find their greatest common factor, these numbers must be factored into prime factors simultaneously, that is, only being divided by numbers of which all three are divisible, thus:
27 - 18 - 30|3
9 - 6 - 10
No numbers by which all of 9, 6 and 10 are divisible, thus, gcf(27,18,30) = 3 and the greatest dimensions each tile can have is of 3 feet.
A similar problem is given at brainly.com/question/6032811
D because 6/20 is correct and the three wrong super wrong hope it helps
Answer:
table A
Step-by-step explanation:
side note: if the outputs have the same numbers there not a function
Answer:
Photomath
Step-by-step explanation:
It looks like someone else is answering this for me so I'll just give ya a nudge. In the future as long as you can put it into an equation Photo math helped me a lot in Middle and Highschool.
