Can I send a picture instead of typing it out?
For a) [Ru(NH₃)₅Cl]SO₄
Ru configuration = d⁶s²
In this complex Ru oxidation number is +3
Ru³⁺ configuration = d⁵
number of
electrons = 5
For b) Na₂[Os(CN)₆]
Os configuration = d⁶s²
In this complex Os oxidation number is +4
Os⁴⁺ configuration = d⁴
number of
electrons = 4
Examples of Everyday Radiation
Non-ionizing Radiation
Visible light
Infrared light
Near ultraviolet light
Microwaves
Low frequency waves
Radio waves
Waves produced by mobile phones
A campfire's heat
Thermal radiation
Extremely low frequency waves (3 - 30 Hz)
Very low frequency waves (3-30 kHz)
Power lines
Strong magnets
MRI
LEDs
Lasers
Light bulbs
Light from the sun
Remote controls
Cordless phones
Radio-frequency radiation such as televisions, FM and AM radio
Shortwave and CB's
Computer screens
Infrared lamps use to maintain food temperature in restaurants
Ionizing Radiation
Ultraviolet light
X-rays
Gamma-rays
Radioactive decay's particles
Cosmic rays
Alpha rays
Beta rays
Medical imaging equipment
Ionization of food
Sterilization of medical tools
Nuclear power production
Metal mining can result in exposure to ionizing radiation
Coal mining and power production from coal
Nuclear weapons
Galactic Cosmic Radiation (to which astronauts are exposed)
Solar Particle Event radiation (to which astronauts may be exposed)
Natural background radiation
Radiation therapy for specific forms of cancer
Radon
CT scans
Nuclear medical scans
X-Rays
Airport security scanners (in extremely high usage)
The volume of CO= 2.912 L
<h3>Further explanation
</h3>
Given
Dehydration of 6 g of methanoic acid with H2SO4
Required
The volume of CO
Solution
Reaction
HCOOH ⇒ CO+H₂O
MW = 1.Ar C+2.Ar H+2.Ar O
MW = 1.12+2.1+2.16
MW= 46 g/mol
mol = mass : MW
mol = 6 g : 46 g/mol
mol = 0.13
From equation, mol ratio HCOOH : CO, so mol CO = 0.13
Vm = 22.4 L
so for 0.13 mol :
= 0.13 x 22.4 L
= 2.912 L
A. Industrial pollution, the rest are considered positive