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Savatey [412]
3 years ago
5

What is meant by the biodegradability of soap molecules

Chemistry
1 answer:
AlekseyPX3 years ago
5 0

Answer:

The biodegradability of soap moleculea means the soap molecules are degradable in nature it doesn't causes water pollution as comparing as detergent..

You might be interested in
Which compound has the smallest mass. H2O CO H2O2 CO2
wolverine [178]
H2O as it has a relative atomic mass of 18
7 0
3 years ago
What is the mass, in grams, of a pure iron cube that has a volume of 3.80 cm?
Trava [24]

Answer:

2.66 g of Fe, can be obtained from the reaction

Explanation:

Let's think the reaction:

2Fe₂O₃   +  6CO  →   4Fe +  6CO₂

Ratio is 2:4, so If i have x moles of iron (III) oxide, I will produce the double of moles of Fe.

Mass / Molar mass = Mol

3.80 g / 159.7 g/m = 0.0237 moles

0.0237 moles . 2 = 0.0475 moles

Molar mass Fe = 55.85 g/m

Mol . Molar mass = Mass → 0.0475 m . 55.85 g/m = 2.66 grams

Explanation:

4 0
3 years ago
Sodium is a highly reactive metal and
sergij07 [2.7K]

Answer:

NaCl

Explanation:

na + cl > nacl

This is also a salt

3 0
3 years ago
What is Mars colonization?
serious [3.7K]

Answer:The colonization of Mars has received interest from public space agencies and private corporations and has received extensive hypothetical treatment in science fiction writing, film, and art.

Explanation:

3 0
3 years ago
An experiment with 55 co takes 47.5 hours. at the end of the experiment, 1.90 ng of 55-co remains. if the half-life is 18.0 hour
Andru [333]

Answer:

\boxed{\text{10.7 ng}}

Explanation:

Let A₀ = the original amount of ⁵⁵Co .

The amount remaining after one half-life is ½A₀.

After two half-lives, the amount remaining is ½ ×½A₀ = (½)²A₀.

After three half-lives, the amount remaining is ½ ×(½)²A₀ = (½)³A₀.

The general formula for the amount remaining is:

A =A₀(½)ⁿ

where n is the number of half-lives

n = t/t_½

Data:

   A = 1.90 ng

    t = 45 h

t_½ = 18.0 h

Calculation:

(a) Calculate n

n = 45/18.0 = 2.5

(b) Calculate A

1.90 = A₀ × (½)^2.5

1.90 = A₀ × 0.178

A₀ = 1.90/0.178 = 10.7 ng

The original mass of ⁵⁵Co was \boxed{\text{10.7 ng}}.

7 0
3 years ago
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