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2 years ago

14

If the diameter of the red marble is 3.0 cm, and by using the formula for volume, what is a good approximation of its volume?

1 answer:

atroni [7]2 years ago

6 0

You can solve for volume using radius or diameter.
Sphere Volume = <span> 4/3 • <span>π <span>• r³ <span> = <span>( <span>π <span>•d³)/6
We're given the diameter so let's use that.
Volume = PI * d^3 / 6
</span></span></span></span></span></span></span>
<span>Volume = 3.14159 * 3.0^3 / 6
</span>
<span>Volume = 3.14159 * 9 / 2

</span><span><span><span><span>Volume = </span>14.137 cubic centimeters
</span></span></span>

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2. The electrical resistance R of a wire varies inversely with the square of its diameter d. If a wire with a

Mariulka [41]

Answer:

$0.225 \Omega =225 m\Omega$

Step-by-step explanation:

We know (Ohm second law) that $R= \frac{k}{d^2}$ where k inlcudes the rest of the parameters (material, lenght). In our situation we have k= $0.4\cdot9 \Omega mm^2$ . The moment the diameter becomes 8mm R becomes

$R= {{0.4\cdot 9}\over{16}} \Omega = 0.225 \Omega$

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2 years ago

Which is a difference of cubes?<br><br> x6 – 27<br> x15 – 36<br> x16 – 64<br> x5 – 125

shutvik [7]

Answer:

The correct option is 1.

Step-by-step explanation:

The difference of cubes is defined as

$a^3-b^3=(a-b)(a^2+ab+b^2)$

The given expression is

$x^6-27$

It can be written as

$x^6-3^3$

Using the property of exponent, the above expression can be written as

$(x^2)^3-3^3$ $[\because (x^m)^n=x^{mn}]$

This is a difference of cubes.

Therefore the correct option is 1.

6 0

3 years ago

Read 2 more answers

What is 3(x+3)+7x= ?

Hitman42 [59]

Answer:

10x+9

Step-by-step explanation:

You first have to multiply 3 into the parenthesis because you have to use distributive property.

Once you do that you get 3x+9+7x.

Combine like terms.

10x+9

6 0

3 years ago

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Find all values of x for which the series converges. (Enter your answer using interval notation.) [infinity] 9 x − 7 9 n n = 0 F

makkiz [27]

Answer:

The series converges to $\frac{1}{1-9x}$ for $\frac{-1}{9} < x < \frac{1}{9}$

Step-by-step explanation:

Given the series is $\sum_{n=0}^{\infty} 9^n x^n$

We have to find the values of x for which the series converges.

We know,

$\sum_{n=0}^{\infty} ar^{n-1}$ converges to (a) / (1-r) if r < 1

Otherwise the series will diverge.

Here, $\sum_{n=0}^{\infty} 9^n x^n = \sum_{n=0}^{\infty} (9x)^{n}$ is a geometric series with |r| = | 9x |

And it converges for |9x| < 1

Hence, the given series gets converge for $\frac{-1}{9} < x < \frac{1}{9}$

And geometric series converges to $\frac{a}{1-r}$

Here, a = 1 and r = 9x

Therefore, $\frac{a}{1-r} = \frac{1}{1-9x}$

Hence, the given series converges to $\frac{1}{1-9x}$ for $\frac{-1}{9} < x < \frac{1}{9}$

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3 years ago

a staind window has an area of 900 square inches one window design is made of rectangles stained glass pieces that are 5 inches

sp2606 [1]

5x3=15

900/15=60

60 pieces make up the window

7 0

2 years ago