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Allisa [31]
3 years ago
15

A group of 8 friends (5 girls and 3 boys) plans to watch a movie, but they have only 5 tickets. If they randomly decide who will

watch the movie, what is the probability that there are at least 3 girls in the group that watch the movie? A. 0. 018 B. 0. 268 C. 0. 536 D. 0. 821.
Mathematics
1 answer:
frutty [35]3 years ago
3 0

Answer:

B. 0.268

Step-by-step explanation:

if there are more than half boys then girls it as t be und .5 since that's half and .018 is to low

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This is due like right now, please help me!!!!
Varvara68 [4.7K]

\bold{\huge{\orange{\underline{ Solution }}}}

\bold{\underline{ Given \: Rules}}

  • <u>The </u><u>sum</u><u> </u><u>of </u><u>the </u><u>number </u><u>in </u><u>each </u><u>of </u><u>the </u><u>four </u><u>rows </u><u>is </u><u>the </u><u>same </u>
  • <u>The </u><u>sum </u><u>of </u><u>the </u><u>numbers </u><u>in </u><u>each </u><u>of </u><u>the </u><u>three </u><u>columns </u><u>is </u><u>the </u><u>same</u>
  • <u>The </u><u>sum </u><u>of </u><u>any </u><u>row </u><u>does </u><u>not </u><u>equal </u><u>the </u><u>sum </u><u>of </u><u>any </u><u>column </u>

\bold{\underline{ Let's \: Begin}}

<u>According </u><u>to </u><u>the </u><u>Second</u><u> </u><u>rule </u><u>:</u><u>-</u>

\sf{ 75+b+83=76+80+d=a+81+85+78+c+e }

\sf{ 158 + b = 156 + d = 166 + a = 78 + c + e ...(1)}

<u>According </u><u>to </u><u>the </u><u>first </u><u>rule </u><u>:</u><u>-</u><u> </u>

\sf{ 75+76+a+78 = b+80+81+c = 83+86+d+e}

\sf{ 229 + a = 161 + b + c = 168 + d + e ...(2)}

<u>From </u><u>(</u><u> </u><u>1</u><u> </u><u>)</u><u> </u><u>we </u><u>got </u><u>:</u><u>-</u>

\sf{ 158 + b = 166 + a, 156 + d = 166 + a }

\sf{ b = 166 - 158 + a,  d = 166 - 156 + a }

\sf{ b = 8 + a,  d = 10 + a ...(3)}

<u>Subsitute </u><u>(</u><u>3</u><u>)</u><u> </u><u>in </u><u>(</u><u> </u><u>2</u><u> </u><u>)</u><u> </u><u>:</u><u>-</u>

\sf{229+a = 161+8+a+c = 168+10+a+e}

\sf{ 229+a = 169+a+c = 178+a+e}

<u>We</u><u> </u><u>can </u><u>write </u><u>it </u><u>as </u><u>:</u><u>-</u>

\sf{ 229+a = 169+a+c \:or\:229+a = 178+a+e}

\sf{ c = 299-169+a-a\:or\:e = 229-178+a-a}

\sf{ c = 60 \: and \: e = 51 }

<u>Subsitute </u><u>the </u><u>value </u><u>of </u><u>c </u><u>and </u><u>e </u><u>in </u><u>(</u><u> </u><u>1</u><u> </u><u>)</u><u>:</u><u>-</u>

\sf{ 158 + b = 156 + d = 166 + a = 78 + 60 + 51 }

\sf{ 158 + b = 156 + d = 166 + a = 189}

<u>Now</u><u>, </u>

\sf{ For \: b,  158 + b = 189 }

\sf{ b = 189 - 158 }

\sf{ b = 31}

\sf{ For \: d ,  156 + b = 189 }

\sf{ d = 189 - 156 }

\sf{ d = 33}

\sf{ For \: a,  166 + a = 189 }

\sf{ a = 189 - 166 }

\sf{ a = 23 }

Hence, The value of a, b, c, d and e is 23, 31 ,60 ,33 and 51 .

8 0
3 years ago
To convert degrees Fahrenheit (F) into degrees Celsius (C) use the formula 2003-05-04-00-00_files/i0150000.jpg. Rewrite the equa
mihalych1998 [28]
To covert degrees Fahrenheit (F) to degrees Celsius (C) we use the equation C<span> = (</span>F<span> - 32) × 5/9</span> . To convert degrees Celsius (C) to degrees <span>Fahrenheit (F) we have to rewrite the equation. 
First step: Divide both sides by 5/9. The equation would look like this: 
</span>C(9/5) = (F - 32) 

Second step: Add 32 on both sides. 
32 + (9/5)C = F or F = <span>32 + (9/5)C</span>
6 0
3 years ago
Can I get a bit of help
Phantasy [73]

she can count the number of row and the number of square in each row, or she can add 6 and 8

5 0
3 years ago
4688-3) -30X-5 CX-5)
pshichka [43]

Answer:

x = 13/3

Step-by-step explanation:

4(8x-3) - 30x = 5(x-5)

Distribute

32x - 12 - 30x  = 5x -25

Combine like terms

2x -12 = 5x-25

Subtract 2x from each side

2x-12-2x = 5x-2x -25

-12 = 3x-25

Add 25 to each side

-12+25 = 3x-25+25

13 = 3x

Divide each side by 3

13/3 = x

4 0
3 years ago
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